Jika koordinat titik P ( 3 , 7 ) \left(3,7\right) ( 3 , 7 ) dan Q ( − 2 , 5 ) \left(-2,5\right) ( − 2 , 5 ) , vektor P Q → \overrightarrow{PQ} P Q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = . . .

( − 5 − 2 ) \left(-5\ -2\right) ( − 5 − 2 )

( 4 − 1 ) \left(4\ -1\right) ( 4 − 1 )

( 6 5 ) \left(6\ 5\right) ( 6 5 )

( 2 11 ) \left(2\ 11\right) ( 2 1 1 )

( − 2 − 11 ) \left(-2\ -11\right) ( − 2 − 1 1 )

Diketahui koordinat titik S ( 4 , 2 ) \left(4,2\right) ( 4 , 2 ) dan vektor S T → \overrightarrow{ST} S T <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 5 3 ) \left(-5\ 3\right) ( − 5 3 ) . Koordinat titik T adalah....

( − 1 , 5 ) \left(-1,5\right) ( − 1 , 5 )

( − 1 , − 5 ) \left(-1,-5\right) ( − 1 , − 5 )

( 1 , 5 ) \left(1,5\right) ( 1 , 5 )

( 5 , − 1 ) \left(5,-1\right) ( 5 , − 1 )

( 5 , 1 ) \left(5,1\right) ( 5 , 1 )

jika vektor P Q ‾ \overline{PQ} P Q = (2,3) dan P R ‾ \overline{PR} P R = (1,5) maka panjang Q R ‾ \overline{QR} Q R =

73 \sqrt{73} 7 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

55 \sqrt{55} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

53 \sqrt{53} 5 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Vektor posisi dari titik Y (12,23) adalah ... .

1 673 ⌈ 12 , 23 ⌉ \frac{1}{\sqrt{673}}\lceil12,\ 23\rceil 6 7 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ⌈ 1 2 , 2 3 ⌉

1 15 ⌈ 23 , 12 ⌉ \frac{1}{15}\lceil23,\ 12\rceil 1 5 1 ⌈ 2 3 , 1 2 ⌉

1 15 ⌈ 12 , 23 ⌉ \frac{1}{15}\lceil12,\ 23\rceil 1 5 1 ⌈ 1 2 , 2 3 ⌉

1 529 ⌈ 12 , 23 ⌉ \frac{1}{\sqrt{529}}\lceil12,\ 23\rceil 5 2 9 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 ⌈ 1 2 , 2 3 ⌉

Vektor u ‾ \overline{u} u dengan panjang 30 membentuk sudut 135 derajat terhadap sumbu x . maka komponen vektor tersebut adalah ... .

( − 15 2 , 15 2 ) \left(-15\sqrt{2},\ 15\ \sqrt{2}\right) ( − 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> , 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

( 15 2 , 15 2 ) \left(15\sqrt{2},\ 15\sqrt{2}\right) ( 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> , 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

( − 15 2 , 15 3 ) \left(-15\sqrt{2},\ 15\sqrt{3}\right) ( − 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> , 1 5 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

( − 15 , 15 2 ) \left(-15,\ 15\sqrt{2}\right) ( − 1 5 , 1 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

VEKTOR 1

Authored by yayah shulhiyyah

Mathematics

11th Grade

CCSS covered

Used 72+ times

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MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Diberikan vektor $\overrightarrow{a}$ , $\overrightarrow{b}$ dan $\overrightarrow{c}$ . Tentukan vektor resultan $\overleftarrow{a}$ + $\overrightarrow{b}$ - $\overrightarrow{c}$ dengan metode poligon

Tags

CCSS.HSN-VM.B.4A

CCSS.HSN-VM.B.4B

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diketahui dua buah vektor seperti berikut.

Hasil dari $\overrightarrow{a\ }\ -\overrightarrow{b\ }$ yang benar dengan metode segitiga adalah ....

Tags

CCSS.HSN-VM.B.4C

MULTIPLE CHOICE QUESTION

30 sec • 12 pts

Disajikan vektor $\overrightarrow{a\ }\$ dan $\overrightarrow{b\ }$ sebagai berikut.

Hasil dari $\overrightarrow{a\ }\ +\overrightarrow{b\ }$ dengan metode jajar genjang adalah ...

Tags

CCSS.HSN-VM.B.4A

CCSS.HSN-VM.B.4B

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Diberikan 3 buah vektor a, b, c seperti gambar di bawah.
Dengan metode poligon tunjukkan :

d = a + b − c

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Besaran yang memiliki nilai dan arah disebut besaran ....

skalar

vektor

pokok

turunan

dimensi

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Tags

CCSS.HSN.VM.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Vektor adalah...

Sebuah garis lurus yang mempunyai nilai

Sebuah garis lurus yang mempunyai arah

sebuah garis lurus yang mempunyai panjang (nilai) dan arah

Garis yang melengkung

Huruf kapitalyang sama panjang

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VEKTOR 1

Diberikan vektor a→\overrightarrow{a}a , b→\overrightarrow{b}b dan c→\overrightarrow{c}c . Tentukan vektor resultan a←\overleftarrow{a}a + b→\overrightarrow{b}b - c→\overrightarrow{c}c dengan metode poligon

Diketahui dua buah vektor seperti berikut. Hasil dari a → −b →\overrightarrow{a\ }\ -\overrightarrow{b\ }a −b yang benar dengan metode segitiga adalah ....

Disajikan vektor a → \overrightarrow{a\ }\ a dan b →\overrightarrow{b\ }b sebagai berikut.Hasil dari a → +b →\overrightarrow{a\ }\ +\overrightarrow{b\ }a +b dengan metode jajar genjang adalah ...

Diberikan 3 buah vektor a, b, c seperti gambar di bawah. Dengan metode poligon tunjukkan : d = a + b − c

Besaran yang memiliki nilai dan arah disebut besaran ....

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Vektor adalah...

A (-3,5) dan B (8,2) maka A + B = ...

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Discover more resources for Mathematics

Diberikan vektor $\overrightarrow{a}$ , $\overrightarrow{b}$ dan $\overrightarrow{c}$ . Tentukan vektor resultan $\overleftarrow{a}$ + $\overrightarrow{b}$ - $\overrightarrow{c}$ dengan metode poligon

Diketahui dua buah vektor seperti berikut.

Hasil dari $\overrightarrow{a\ }\ -\overrightarrow{b\ }$ yang benar dengan metode segitiga adalah ....

Disajikan vektor $\overrightarrow{a\ }\$ dan $\overrightarrow{b\ }$ sebagai berikut.

Hasil dari $\overrightarrow{a\ }\ +\overrightarrow{b\ }$ dengan metode jajar genjang adalah ...

Diberikan 3 buah vektor a, b, c seperti gambar di bawah.
Dengan metode poligon tunjukkan :

d = a + b − c