− 8 + log ⁡ 6 ( x + 1 ) = − 7 -8\ +\ \log_6\ \left(x\ +\ 1\right)\ =\ -7 − 8 + lo g 6 ( x + 1 ) = − 7

− 1000 9 -\frac{1000}{9} − 9 1 0 0 0

9 + 10 log ⁡ 8 ( − 8 x ) = 19 9\ +\ 10\log_8\ \left(-8x\right)\ =\ 19 9 + 1 0 lo g 8 ( − 8 x ) = 1 9

246 49 \frac{246}{49} 4 9 2 4 6

− 27 4 -\frac{27}{4} − 4 2 7

log ⁡ 5 ( 8 − 10 n ) = − 2 \log_5\ \left(8-10n\right)\ =\ -2 lo g 5 ( 8 − 1 0 n ) = − 2

199 250 \frac{199}{250} 2 5 0 1 9 9

4099 5 \frac{4099}{5} 5 4 0 9 9

577 384 \frac{577}{384} 3 8 4 5 7 7

− 31 10 -\frac{31}{10} − 1 0 3 1

7 log ⁡ 5 ( − 6 v − 1 ) = 0 7\log_5\ \left(-6v\ -\ 1\right)\ =\ 0 7 lo g 5 ( − 6 v − 1 ) = 0

− 2053 5 -\frac{2053}{5} − 5 2 0 5 3

5 log ⁡ 6 ( − 5 k − 9 ) + 2 = 17 5\log_6\ \left(-5k\ -\ 9\right)\ +\ 2\ =\ 17 5 lo g 6 ( − 5 k − 9 ) + 2 = 1 7

− 6571 9 -\frac{6571}{9} − 9 6 5 7 1

log ⁡ 4 7 + log ⁡ 4 ( x − 2 ) = log ⁡ 4 62 \log_4\ 7\ +\ \log_{4\ }\ \left(x\ -\ 2\right)\ =\ \log_4\ 62 lo g 4 7 + lo g 4 ( x − 2 ) = lo g 4 6 2

− 19 6 -\frac{19}{6} − 6 1 9

log ⁡ 4 6 − log ⁡ 4 4 x = log ⁡ 4 63 \log_4\ 6\ -\ \log_4\ 4x\ =\ \log_{4\ }63 lo g 4 6 − lo g 4 4 x = lo g 4 6 3

− 5 16 -\frac{5}{16} − 1 6 5

log ⁡ 7 ( x + 4 ) − log ⁡ 7 x = log ⁡ 7 33 \log_7\ \left(x\ +\ 4\right)\ -\ \log_{7\ }x\ =\ \log_{7\ }33 lo g 7 ( x + 4 ) − lo g 7 x = lo g 7 3 3

− 60 7 -\frac{60}{7} − 7 6 0

Solving Log Equations

Quiz

•

Mathematics

•

10th - 12th Grade

•

Practice Problem

•

Easy

•

CCSS

HSF.BF.B.5, HSA.REI.A.1, HSA.CED.A.1

+3

Standards-aligned

Jodie Craft

Used 577+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\log\ \left(9-x\right)=\log\ \left(2x-6\right)$

5

-11

$\frac{18}{19}$

-4

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.BF.B.5

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\log_3\left(n^2+4n\right)=\log_3\left(35+2n\right)$

5

5, -7

-3, 5

-7

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

log₁₁b = 3

1331

16

1000

$\frac{1}{9}$

Tags

CCSS.HSF.BF.B.5

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$6\ +\ \log_2\ x\ =\ 6$

9

$\frac{1}{10}$

1

121

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

-10log₂x + 8 = -12

8

12

1296

4

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\log_9\left(r-8\right)\ =\ 2$

55

$\frac{11}{6}$

89

6

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$-8\ +\ \log_6\ \left(x\ +\ 1\right)\ =\ -7$

5

6

$-\frac{1000}{9}$

124

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

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Solving Log Equations

20 questions

$\log\ \left(9-x\right)=\log\ \left(2x-6\right)$

$\log_3\left(n^2+4n\right)=\log_3\left(35+2n\right)$

log₁₁b = 3

$6\ +\ \log_2\ x\ =\ 6$

-10log₂x + 8 = -12

$\log_9\left(r-8\right)\ =\ 2$

$-8\ +\ \log_6\ \left(x\ +\ 1\right)\ =\ -7$

$9\ +\ 10\log_8\ \left(-8x\right)\ =\ 19$

$\log_5\ \left(8-10n\right)\ =\ -2$

$7\log_5\ \left(-6v\ -\ 1\right)\ =\ 0$

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Solving Log Equations

20 questions

log⁡ (9−x)=log⁡ (2x−6)\log\ \left(9-x\right)=\log\ \left(2x-6\right)log (9−x)=log (2x−6)

log⁡3(n2+4n)=log⁡3(35+2n)\log_3\left(n^2+4n\right)=\log_3\left(35+2n\right)log3​(n2+4n)=log3​(35+2n)

log11 b = 3

6 + log⁡2 x = 66\ +\ \log_2\ x\ =\ 66 + log2​ x = 6

-10log2 x + 8 = -12

log⁡9(r−8) = 2\log_9\left(r-8\right)\ =\ 2log9​(r−8) = 2

−8 + log⁡6 (x + 1) = −7-8\ +\ \log_6\ \left(x\ +\ 1\right)\ =\ -7−8 + log6​ (x + 1) = −7

9 + 10log⁡8 (−8x) = 199\ +\ 10\log_8\ \left(-8x\right)\ =\ 199 + 10log8​ (−8x) = 19

log⁡5 (8−10n) = −2\log_5\ \left(8-10n\right)\ =\ -2log5​ (8−10n) = −2

7log⁡5 (−6v − 1) = 07\log_5\ \left(-6v\ -\ 1\right)\ =\ 07log5​ (−6v − 1) = 0

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$\log\ \left(9-x\right)=\log\ \left(2x-6\right)$

$\log_3\left(n^2+4n\right)=\log_3\left(35+2n\right)$

log₁₁b = 3

$6\ +\ \log_2\ x\ =\ 6$

-10log₂x + 8 = -12

$\log_9\left(r-8\right)\ =\ 2$

$-8\ +\ \log_6\ \left(x\ +\ 1\right)\ =\ -7$

$9\ +\ 10\log_8\ \left(-8x\right)\ =\ 19$

$\log_5\ \left(8-10n\right)\ =\ -2$

$7\log_5\ \left(-6v\ -\ 1\right)\ =\ 0$