Derivative of Natural logarithms

Derivative of Natural logarithms

12th Grade - University

8 Qs

quiz-placeholder

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Derivative of Natural logarithms

Derivative of Natural logarithms

Assessment

Quiz

Mathematics

12th Grade - University

Medium

CCSS
HSF.IF.C.8, HSF-IF.C.8B, HSF.TF.A.1

+6

Standards-aligned

Created by

Dima Halawa

Used 81+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of  y=ln8xy=\ln8x  

 y=18xy'=\frac{1}{8x}  

 y=1xy'=\frac{1}{x}  

 y=8xy'=8x  

 y=xy'=x  

Tags

CCSS.HSF-IF.C.8B

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of  y=lnxy=\ln\sqrt{x}  

 y=1xy'=\frac{1}{\sqrt{x}}  

 y=1xy'=\frac{1}{x}  

 y=12xy'=\frac{1}{2x}  

 y=xy'=\sqrt{x}  

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

CCSS.HSN.RN.A.1

CCSS.HSN.RN.A.2

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of y=ln(lnx)y=\ln\left(\ln x\right)  

 y=1x1lnxy'=\frac{1}{x}\cdot\frac{1}{\ln x}  

 y=1xy'=\frac{1}{x}  

 y=ln2xy'=\ln^2x  

 y=1lnxy'=\frac{1}{\ln x}  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of  y=lnsecxy=\ln\sec x  

 y=tanxy'=\tan x  

 y=1secxy'=\frac{1}{\sec x}  

 y=1y'=1  

 y=1cosxy'=\frac{1}{\cos x}  

Tags

CCSS.HSF.TF.A.1

CCSS.HSF.TF.A.2

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of  y=lnxy=\sqrt{\ln x}  

 y=12lnxy'=\frac{1}{2}\ln x  

 y=12xlnxy'=\frac{1}{2x\sqrt{\ln x}}  

 y=12xy'=\frac{1}{2x}  

 y=lnxy'=\sqrt{\ln x}  

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Find the derivative of  y=lnxlnxy=\ln x\cdot\ln x  

 y=1x2y'=\frac{1}{x^2}  

 y=lnxxy'=\frac{\ln x}{x}  

 y=2xy'=\frac{2}{x}  

 y=2lnxxy'=\frac{2\ln x}{x}  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the derivative of  y=lnπy=\ln\pi  

 y=lnπy'=\ln\pi  

 y=1πy'=\frac{1}{\pi}  

 y=1y'=1  

 y=0y'=0  

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Find the derivative of  y=lnxxy=\frac{\ln x}{x}  

 y=1x2y'=\frac{1}{x^2}  

 y=1xy'=\frac{1}{x}  

 y=1lnxx2y=\frac{1-\ln x}{x^2}  

 y=xlnxx2y'=\frac{x-\ln x}{x^2}  

Tags

CCSS.HSF.IF.C.8