Assessment 2 (HS)

-3a + 8 = 14

• a= -2
• a= -7.5
• a= 2
• a= 6

Tags

CCSS.7.EE.B.4A

The first step in solving using the substitution method is __________.

• get x by itself

• get y by itself

• get either variable by itself in one equation

• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:
-4x + 4y = 8
y = -2x - 10

• (-4, -2)
• (12, -34)
• (4, -18)
• (-2, -6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution.

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The first step in solving using the substitution method is __________.

• get x by itself
• get y by itself
• get either variable by itself
• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step in solving a system of equations by elimination/matrices?

• Get both equations in standard form and line up the like terms.

• Get both equations in slope-intercept form.

• Get both equations equal to zero.

• Put the x terms first.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which is the best method to use?

y = 6x − 11

−2x − 3y = −7

• Graphing

• Substitution because a variable is isolated.

• Elimination because both equations are in standard form.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by elimination.

8x +10y = - 20

−8x − 6y = −4

• Infinite number of solutions

• (6, 5)

• (−6, −5)

• (5, −6)

• No Solution

Tags

CCSS.8.EE.C.8B

Find x and y using the elimination method
2x+3y=7
2x+7y=11

• x=-2, y=-1
• x=2, y=-1
• x=2, y=1
• x=-2, y=1

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
7x-9y=29

7x+2y=-15

• (-4,-1)
• (-1.-4)
• (-1,4)
• (-1,6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6