Congruency Proof of Triangles

If DA is perpendicular to IE, then we can immediately conclude that

• $IA=AE$

• $\angle IAD=\angle DAE$

• $\angle IDA=\angle EDA$

• $\angle IAD\ \&\ \angle DAE$ are right angles

If DA bisects EI, then

• $\angle IDA=\angle EDA$

• AI=EA

• Both 1 and 2 are correct

• DI=ED

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.5

In this picture, we know for sure that

• $\angle TEB=\angle ETS$

• $\angle BTE=\angle SET$

• BE=ST

• Both 1 and 2 are correct

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.5

In this picture,

• $\angle BCA=\angle DCE$ (vertically opposite angles)

• $\angle C=\angle C$ (vertically opposite angles)

• $\angle EDA=\angle BAD\$ (vertically opposite angles)

• None of the above; we don't actually have vertical opposite angles

How are the triangles congruent?

• AAS

• SAS

• RHS

• SSS

How are the triangles congruent?

• SAS

• SSS

• AAS

• RHS

How are the triangles congruent?

• RHS

• SAS

• AAS

• SSS

Which line is incorrect in the proof?

•  $\angle CAB=\angle FDE\ \left(given\right)$  

•  $\angle BCA=\angle EFD\ \left(given\right)$  

•  $BC=EF\ \left(given\right)$  

•  $\therefore\Delta ABC\ \equiv\Delta DEF\ \left(AAS\right)$  

Which line is incorrect in the proof?

• $AB=DE\left(given\right)$

• $\angle B=\angle E\left(given\right)$

• $BC=EF\ \left(given\right)$

• $\therefore\Delta ABC\ \equiv\Delta DEF\ \left(SAS\right)$