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EM-III

Authored by Laxman Sawant

Mathematics

University

Used 13+ times

EM-III
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9 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1) which of the following is the general solution to d2y /dx2 + 3dy /dx − 10y = 0?

In each case, A and B are arbitrary constants. Exactly one option must be correct)

y = Ae2x + Be−5x

y = Ae−2x + Be5x

y = Ae2x + Be5x

y = Ae−2x + Be−5x

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1) Which of the following is the general solution to d2y /dt2 - 4dy/ dt +4y = 0?

In each case, A and B are arbitrary constants. Exactly one option must be correct)

y = Ae2t + Bte2t

y = Ae2t + Be−2t

y = Ae2t + Be−6t

y = Ae(−2+22)t + Be(−2−22)t

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1) Which of the following are general solutions to d2x/ dt2 − 4dx/ dt + 13x = 0?

In each case, A and B are arbitrary constants.

x = Ae5t + Be−t

x = Ae(2+3i)t + Be(-2−3i)t

x = e2x(Acos3x + Bsin3x)

x = e3x(Acos2x + Bsin2x)

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1) Which of the following is the general solution to d2y/dx2 + 10dy/dx + 25y = 0?

In each case, A and B are arbitrary constants. Exactly one option must be correct)

y = Ae−5x + Be−5x

y = Axe−5x + Be−5x

y = Ae5x + Be5x

y = Axe5x + Be5x

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1) Consider the differential equation d2y /dx2 − 49y = 0.

Which of the following options is correct? Exactly one option must be correct)

The roots of the auxiliary equation are 0 and 7.

There is no auxiliary equation for a differential equation of this type.

The auxiliary equation has a repeated root of 7.

The roots of the auxiliary equation are 7 and −7

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The general solution to d2z /dt2 + 6dz/dt + 9z = 0 is

z = Ate−3t + Be−3t. Which of the following options is correct?

As t →∞, z → A for any value of B.

The behaviour of z as t →∞ depends on the values

of A and B.

As t →∞, z → 0 for any values of A and B.

As t →∞, z →∞ for any values of A and B.

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the general solution to d2y/dt2 − 3dy/dt − 4y = 0 satisfying y(0) = 0 and y′(0) = 5.

y = et − e−4t

y = e−t − e4t

y = e−4t − et

y = e4t − e−t

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