Chapter 3 Test AP Calc

Chapter 3 Test AP Calc

11th - 12th Grade

7 Qs

quiz-placeholder

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Chapter 3 Test AP Calc

Chapter 3 Test AP Calc

Assessment

Quiz

Mathematics

11th - 12th Grade

Medium

CCSS
HSF-BF.B.4A, HSF.IF.B.4

Standards-aligned

Created by

Michelle Walton

Used 3+ times

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

if  x2+y2=a2x^2+y^2=a^2  , where a is a constant, find  d2ydx2\frac{d^2y}{dx^2}  .

 a2y3\frac{-a^2}{y^3}  

 x2y2y3\frac{x^2-y^2}{y^3}  

 y2x2y2\frac{-y^2-x^2}{y^2}  

 1a2\frac{1}{a^2}  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For the function ff   ,  f'\left(x\right)=4x-3  and  f(2)=4. f\left(2\right)=4.\   What is the approximation for  f(2.1)f\left(2.1\right)  found by using the tangent line to the graph of  ff  at  x=2.x=2.  

-2.6

4.5

4.8

5.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Let  ff  be a differentiable function such that  f(4)=12, f(9)=4, f(4)=6, f(9)=3.f\left(-4\right)=12,\ f\left(9\right)=-4,\ f'\left(4\right)=-6,\ f'\left(9\right)=3.  The function  gg  is differentiable and  g(x)=f1(x)g\left(x\right)=f^{-1}\left(x\right)  for all x.  What is the value of  g(4)?g'\left(-4\right)?  

 16-\frac{1}{6}  

 14-\frac{1}{4}  

 13\frac{1}{3}  

 19\frac{1}{9}  

Tags

CCSS.HSF-BF.B.4A

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 f(x)=(2x+1)(x23)4, then f;(x)=f\left(x\right)=\left(2x+1\right)\left(x^2-3\right)^4,\ then\ f;\left(x\right)=  

if

 4(2x+1)(x23)34\left(2x+1\right)\left(x^2-3\right)^3  

 8x(2x+1)(x23)38x\left(2x+1\right)\left(x^2-3\right)^3  

 2(x23)3(3x2+x3)2\left(x^2-3\right)^3\left(3x^2+x-3\right)  

 2(x23)3(9x2+4x3)2\left(x^2-3\right)^3\left(9x^2+4x-3\right)  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

217\frac{2}{17}

117\frac{1}{17}

215-\frac{2}{15}

115-\frac{1}{15}

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

1 and 5 only

2 only

1, 3, and 5 only

1, 3, 4, and 5 only

Tags

CCSS.HSF.IF.B.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the equation of the tangent line to x3+y3=3xy+5x3yx^3+y^3=3xy+5x-3y  at (2, 2).


 y=19(x2)+2y=\frac{-1}{9}\left(x-2\right)+2  

 y=133(x2)+2y=\frac{13}{3}\left(x-2\right)+2  

 y=2y=2  

 y=19(x2)+2y=\frac{1}{9}\left(x-2\right)+2