Trig: Test 3 on Review Material

Solve for x:

x² - 14x - 51=0

• x= 17, -3

• x= -17, 3

• x= -17, -3

• x = 17, 3

Factor

6r² - 60r

• 6r(r - 10)

• 6r( r+ 1)

• 6(r + 10)

• (3r + 10)(2r - 6)

Solve:

 $12<-2x-4\le16$  
Write answer in interval notation.

•  $\left(-10,\ -8\right]$  

•  $\left[-10,\ -8\right]$  

•  $\left(-10,\ -8\right)$  

•  $\left[-10,\ -8\right)$  

What is the solution?

• No solution
• (0, 2)
• (0, -4)
• (3, -3)

Tags

CCSS.8.EE.C.8A

Solve the system of equations.
y = 4x+1
3x + 2y = 13

• (1, 5)
• (5, 1)
• (0.25, 2)
• ∅

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations by elimination.
-x + y = -13
-8x - 4y = -8 

• (5, 8)
• (5, -8)
• (-5, -18)
• (-5, 8)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by cross-multiplying

• x = 6

• x = - 6

• x = 6/7

• x = - 6/7

What is the correct ratio?

• sin 40 = w/28

• cos 40 = w/28

• tan 40 = w/28

• sin 40 = 28/w

For the above right triangle, find the side length of x. Round your answer to the nearest hundredth.

• 13.04

• 8.49

• 72.00

• 10.23

Use the above triangle to find  $\cos B$  ,  $\tan B$  , and  $\sin B$  

•  $\cos B=\frac{15}{17},\ \tan B=\frac{15}{8},\ \sin B=\frac{8}{17}$  

•  $\cos B=\frac{8}{17},\ \tan B=\frac{15}{8},\ \sin B=\frac{15}{17}$  

•  $\cos B=\frac{15}{17},\ \tan B=\frac{8}{15},\ \sin B=\frac{8}{17}$  

•  $\cos B=\frac{8}{15},\ \tan B=\frac{8}{17},\ \sin B=\frac{15}{17}$