Basic Differentiation Rules

Basic Differentiation Rules

12th Grade

20 Qs

quiz-placeholder

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Basic Differentiation Rules

Basic Differentiation Rules

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Medium

CCSS
HSA.APR.D.6, HSN.RN.A.2, HSA.APR.A.1

+2

Standards-aligned

Created by

Hassan Hleihel

Used 23+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given  f(x)=3x2+2x1f\left(x\right)=3x^2+2x-1  , which of the following is the correct derivative?

 f(x)=6x2+2f'\left(x\right)=6x^2+2  

 f(x)=6x+2f'\left(x\right)=6x+2  

 f(x)=6x2+2f'\left(x\right)=6x^2+2  

 f(x)=6x2+2x2xf'\left(x\right)=6x^2+2x^2-x  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the slope of the tangent line of the graph of  f(x)=x24xf\left(x\right)=x^2-4x  at the point (-2, 12) ?

 m=8m=8  

  m=8m=-8 

 m=4m=-4  

 m=4m=4  

3.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

Given f(x)=17f\left(x\right)=17  , what is the derivative of  f(x)f\left(x\right)  ?

 f(x)=17xf'\left(x\right)=17x  

 f(x)=17f'\left(x\right)=17  

 f(x)=0f'\left(x\right)=0  

 f(x)=17x2f'\left(x\right)=17x^2  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given f(x)=2x2+4x64xf\left(x\right)=\frac{2x^2+4x-6}{4x}  , find  f(x)f'\left(x\right)  .

 f(x)=4x+44f'\left(x\right)=\frac{4x+4}{4}  

 f(x)=x+1f'\left(x\right)=x+1  

 f(x)=x2+2x32xf'\left(x\right)=\frac{x^2+2x-3}{2x}  

 f(x)=12+32x2f'\left(x\right)=\frac{1}{2}+\frac{3}{2x^2}  

Tags

CCSS.HSA.APR.D.6

5.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

Given f(x)=3xf\left(x\right)=3x  , which of the following is the derivative of the function?

 h(x)=3h'\left(x\right)=3  

 q(x)=3q'\left(x\right)=3  

 b(x)=3b'\left(x\right)=3  

 f(x)=3f'\left(x\right)=3  

6.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

Media Image

Differentiate with respect to x.

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Media Image
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7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Differentiate with respect to x. y=1x3y=\frac{1}{x^3}  


 yx=1x4\frac{\partial y}{\partial x}=\frac{1}{x^4}  

 yx=3x\frac{\partial y}{\partial x}=-3x  

 yx=3x3\frac{\partial y}{\partial x}=-\frac{3}{x^3}  

 yx=3x4\frac{\partial y}{\partial x}=-\frac{3}{x^4}  

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