TEST PERCENT OF CHANGE

Sally went to the clearance rack at a department store and found a shirt she wanted to buy.  The shirt was $36.00 and is on sale for $24.00.  What is the percent of the decrease?

• 33%
• 67%
• 50%
• 34%

Tags

CCSS.6.RP.A.3C

Mary lost 30 pounds.  Before her diet she weighed 180 pounds.  What is the percent of change?

• 17% Decrease
• 18% Decrease
• 19% Decrease
• 20% Decrease

Tags

CCSS.7.RP.A.2

CCSS.7.RP.A.3

The regular price of a scooter is $65.50. It is on sale for $52.40. What is the percent decrease from the regular price to the sale price of the scooter? 

• 35%
• 25%
• 30%
• 20%

Tags

CCSS.6.RP.A.3C

The number of people signed up for a bus trip increased from 32 to 45. What is the percent increase? Round to the nearest percent.

• 52%
• 41%
• 42%
• 45%

Tags

CCSS.6.RP.A.3C

Find each percent increase. Round to the nearest percent.
From 13 friends to 14 friends  

• 20%
• 12%
• 15%
• 8%

Tags

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Find each percent decrease. Round to the nearest percent.
From $80 to $64 

• 35%
• 10%
• 20%
• 25%

Tags

CCSS.7.RP.A.3

A tank of water starts the day with 12 gallons. By the end of the day, the tank of the water has 8.4 gallons. What was the percent of change of the water in the tank?

• 3.6%

• 4.2%

• 30%

• 70%

Tags

CCSS.7.RP.A.2

CCSS.7.RP.A.3

When a garden plot was measured, the dimensions were 102 in x 54 in. Use the greatest possible error to find the minimum and maximum possible areas.

•  $Min:\ 5,260.25\ in^2,\ Max:\ 5,879.25\ in^2$ 

•  $Min:\ 4,300.5\ in^2,\ Max:\ 6,765.5\ in^2$ 

•  $Min:\ 5,430.25\ in^2,\ Max:\ 5,586.25\ in^2$ 

•  $Min:\ 5,555.25\ in^2,\ Max:\ 6,666.25\ in^2$ 

Valerie's jewelry box measures 6.5 cm x 10.8 cm x 5.5 cm. Find the percent error in calculating its volume. (Round each volume to the nearest tenths)

• About 0.21%.

• About 2.1%.

• About 3.2%.

• About 2.8%.

David measured a rectangle as 9.4 in. by 8.3 in. Which is the maximum possible area?

•  $78.91\ in^2$ 

•  $75.75\ in^2$ 

•  $77.13\ in^2$ 

•  $78.02\ in^2$