Holes and Vertical Asymptotes

Holes and Vertical Asymptotes

9th - 12th Grade

20 Qs

quiz-placeholder

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Holes and Vertical Asymptotes

Holes and Vertical Asymptotes

Assessment

Quiz

Mathematics

9th - 12th Grade

Medium

CCSS
HSA.APR.D.7, HSA.APR.D.6, HSA.APR.B.3

+5

Standards-aligned

Created by

KATELYN HAYES

Used 366+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the definition of an ASYMPTOTE?
A curved line. 
A line that only touches the origin. 
A line that only lives on the first quadrant. 
A line that a curve approaches, as it heads towards infinity. 

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The equation of a vertical asymptote is written in the form:

x=

y=

none of the above

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following is determined by just looking at the denominator?
vertical asymptote
horizontal asymptote
holes
slant asymptote

4.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Find the vertical asymptote.

 g(x)=(x+3)(x2)(x+5)(2x1)g\left(x\right)=\frac{\left(x+3\right)\left(x-2\right)}{\left(x+5\right)\left(2x-1\right)}  

x=-5

x=1/2

x=-1/2

x=-3

x=2

Tags

CCSS.HSA.APR.D.7

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Does this function have any vertical asymptotes? If so, what are their equations? y=(x+3)(x4)(x+7)(x4)y=\frac{\left(x+3\right)\left(x-4\right)\left(x+7\right)}{\left(x-4\right)}   

No vertical asymptotes.

One vertical asymptote: x = 4

Two vertical asymptotes: x = -3 and x = -7

Three vertical asymptotes:  x = -3, x = 4, and x = -7

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The holes of a rational function occur when :
my pencil pokes a hole in the paper I'm working on
there is something left in the denominator
the value of f(0)
a factor in the denominator cancels with a factor in the numerator

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.7

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the x-value of the hole? g(x)=(x2)(x+6)(x+2)(x2)g\left(x\right)=\frac{\left(x-2\right)\left(x+6\right)}{\left(x+2\right)\left(x-2\right)}  

2

-2

-6

6

Tags

CCSS.HSA.APR.B.3

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