F.TF Precalculus

2.  Determine an equation for this graph:

• y=sec(x)
• y=2sec(x)
• y=2csc(x)
• y= csc(2x)

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSF.TF.A.4

CCSS.HSF.TF.B.5

3.  Determine an equation for this graph:

• y=csc(x)
• y=sec(x)
• y=cot(x)
• y= tan(x)

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSF.TF.A.2

CCSS.HSF.TF.A.4

CCSS.HSF.TF.B.5

16.  Which equation matches the graph?

• -tan(x-π/2)
• -tan(x+π/2)
• cot(x+π/2)
• -cot(x+π/2)

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

• A
• B
• C
• D

Tags

CCSS.HSF-IF.C.7E

• A

• B

• C

• D

17. Given the equaiton 

 $f\left(x\right)\ =\ -\tan\left(2x+\frac{\pi}{3}\right)$  what would be the correct break down.

• Amplitude = -1, Period =  $\pi$  , Phase Shift =  $\frac{\pi}{4}$  , and the first x-value is  $-\frac{\pi}{6}$  

• Amplitude = 1, Period =  $\pi$  , Phase Shift =  $\frac{\pi}{4}$  , and the first x-value is  $\frac{\pi}{6}$  

• Amplitude = 1, Period =  $2\pi$  , Phase Shift =  $\frac{\pi}{2}$  , and the first x-value is  $-\frac{\pi}{6}$  

• Amplitude = -1, Period =  $2\pi$  , Phase Shift =  $\frac{\pi}{2}$  , and the first x-value is  $\frac{\pi}{6}$  

Is this a pythagorean identity?
tan²x + 1 = secx

• Yes
• No

Tags

CCSS.HSF.TF.C.8

What is csc(x) equivalent to?

• 1/sin(x)
• 1/tan(x)
• sin(x)
• 1/cos(x)

Tags

CCSS.HSF.TF.A.4

Please select the correct solution

• csc x
• sec x
• cot x
• tan x

Tags

CCSS.HSF.TF.C.8

• A

• B

• C

• D