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Тригонометрические уравнения

Authored by Ирина Ивановна

Mathematics

10th Grade

Used 2+ times

Тригонометрические уравнения
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5 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 cos(x+π3)=32\cos\left(x+\frac{\pi}{3}\right)=-\frac{\sqrt{3}}{2}  

 x=±π6π3+2πnx=\pm\frac{\pi}{6}-\frac{\pi}{3}+2\pi n  

 x=±5π6+π3+πnx=\pm\frac{5\pi}{6}+\frac{\pi}{3}+\pi n  

 x=±5π6π3+2πnx=\pm\frac{5\pi}{6}-\frac{\pi}{3}+2\pi n  

 x=±2π3+2πnx=\pm\frac{2\pi}{3}+2\pi n  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 tg(4xπ4)=33tg\left(4x-\frac{\pi}{4}\right)=-\frac{\sqrt{3}}{3}  

 x=π24+πn4x=\frac{\pi}{24}+\frac{\pi n}{4}  

 x=π48+πn4x=\frac{\pi}{48}+\frac{\pi n}{4}  

 x=13π48+πn4x=\frac{13\pi}{48}+\frac{\pi n}{4}  

 x=5π48+4πnx=\frac{5\pi}{48}+4\pi n  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 sin(x+π4)=22\sin\left(x+\frac{\pi}{4}\right)=-\frac{\sqrt{2}}{2}  

 x=(1)nπ4+π4+πnx=\left(-1\right)^n\cdot\frac{\pi}{4}+\frac{\pi}{4}+\pi n  

 x=π2+πnx=\frac{\pi}{2}+\pi n  

 x=(1)n+1π4π4+πnx=\left(-1\right)^{n+1}\cdot\frac{\pi}{4}-\frac{\pi}{4}+\pi n  

 x=(1)nπ2+πnx=\left(-1\right)^n\cdot\frac{\pi}{2}+\pi n  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 sin2x=32\sin2x=\frac{\sqrt{3}}{2}  

 x=(1)n2π3+2πnx=\left(-1\right)^n\cdot\frac{2\pi}{3}+2\pi n  

 x=(1)nπ6+πnx=\left(-1\right)^n\cdot\frac{\pi}{6}+\pi n  

 x=π6+πnx=\frac{\pi}{6}+\pi n  

 x=(1)nπ6+πn2x=\left(-1\right)^n\cdot\frac{\pi}{6}+\frac{\pi n}{2}  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 ctg(x+π4)=3\operatorname{ctg}\left(x+\frac{\pi}{4}\right)=-\sqrt{3}  

 x=7π6+πnx=\frac{7\pi}{6}+\pi n  

 x=7π12+πnx=\frac{7\pi}{12}+\pi n  

 x=5π12+πnx=-\frac{5\pi}{12}+\pi n  

 x=π12+πnx=\frac{\pi}{12}+\pi n  

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