Completing the Square

$\frac{-b}{2a}$

$\left(\frac{b}{2}\right)^2$

$b^2-4ac$

none of the above

Square root both sides

Add 16 to both sides

Factor the trinomial

 $\left(x+5\right)^2$  

 $\left(x+3\right)\left(x+2\right)$  

 $\left(x+3\right)^2$  

Square root both sides

Divide both sides by 2

Subtract 3 from both sides

x = 2

x = 8

x = -2

x = -8

they should've added 14 to both sides instead of 49

they added 32 + 49 wrong

they subtracted wrong at the very end

the factored form should be

the second solution should be -4 instead of 4

in the second step they should've added 2 to both sides instead of 1

they square rooted incorrectly

they factored the trinomial wrong