6-3 and 6-5 log

Write in exponential form.
log₂(¹/₈) = -3

• 2^-3 = ¹/₈
• 2^1/8 = -3
• -3² = ¹/₈
• -3^1/8 = 2

Evaluate by thinking 4 to what power is 16, so

log₄16

• 2

• 4

• 1/2

• -2

Rewrite log_pt = m in exponential form.

• p^t = m
• t^m = p
• m^t = p
• p^m = t

Rewrite in logarithmic form. 7⁰=1

• log₀7=1
• log₇0=1
• log₇1=0
• log₁7=0

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Use properties of Logs to write  $\log_3\left(4\right)-\log_3\left(x\right)+\log_3\left(y\right)$  

as one Log

•  $\log_3\left(\frac{4x}{y}\right)\$ 

•  $\log_3\left(4xy\right)$ 

•  $\log_3\left(\frac{4}{xy}\right)$ 

•  $\log_3\left(\frac{4y}{x}\right)$ 

Use properties of Logs to write  $2\log_3\left(a\right)+2\log_3\left(b\right)$  

as one Log

•  $\log_3\left(2ab\right)\$ 

•  $\log_3\left(a^2b\right)$ 

•  $\log_3\left(ab\right)^2$ 

•  $\log_3\left(a+b\right)^2$ 

Expand  $\log_2\left(3y^2\right)$  

•  $\log_2\left(3\right)\ +\ \log_2\left(y\right)$ 

•  $2\log_2\left(3\right)\ +\ 2\log_2\left(y\right)$ 

•  $\log_2\left(3\right)\ +\ 2\log_2\left(y\right)$ 

•  $\log_2\left(\frac{3}{y^2}\right)\$ 

Expand:  $\log_74\sqrt{d}$  

•  $\log_7\ 4\ -\ \frac{1}{2}\log_7\ d$  

•  $4\log_7d\ +\log_7\ \frac{1}{2}$  

•  $\log_7\ 4+\frac{1}{2}\log_7\ d$  

•  $\frac{1}{2}\log4d$