Prop. of Logarithms and solving Logarithmic and Exp. Eq.

Solve:

log₃(x - 5) = 2

• 25

• 5

• 130

• 14

Solve:

log₂ x + log₂ (x + 5) = log₂ (3x + 8)

• x = 2

• x = -4

• x = 2 and x = -4

• no solution

Solve:

log₆(2x + 3) = 3

• x = 106.5

• x = 100

• x = 16

• x = 50

Solve the equation:

  $4^{2x\ }=\ 7$  

• 0

• 1.311

• .364

• .702

Solve the equation:

  $32^{\left(-3x+1\right)}=\left(\frac{1}{4}\right)^{5x}$  

• 1

•  $\frac{1}{8}$  

• 5

•  $\frac{1}{5}$  

Solve the equation: 

 $625^{-3x}=125^{\left(2x+2\right)}$  

•  $0$  

•  $1$  

•  $-\frac{1}{3}$  

•  $-9$  

Solve the equation: 

 $5^{\left(2-3x\right)}=25$  

•  $\frac{7}{5}$  

•  $-\frac{3}{4}$  

•  $-\frac{7}{6}$  

•  $0$  

To solve, 16^5x = 64^x+7, what would be the correct set-up?

There is more than one correct answer.

• 4^4(5x)=4^16(x+7)

• 8^2(5x)=8^8(x+7)

• 4^2(5x)=4^3(x+7)

• 2^4(5x)=2^6(x+7)

Solve:

log(x) + log(x+3) = 1

• 5

• -2

• -5

• 2

The first step to solve 8 + log 7 = 10 is...

• Rewrite exponentially

• Subtract 8 on both sides to isolate the log

• Divide by 7 on both sides