INTEGRACIÓN MEDIANTE FRACCIONES PARCIALES

INTEGRACIÓN MEDIANTE FRACCIONES PARCIALES

University

5 Qs

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INTEGRACIÓN MEDIANTE FRACCIONES PARCIALES

INTEGRACIÓN MEDIANTE FRACCIONES PARCIALES

Assessment

Quiz

Mathematics

University

Hard

Created by

Jesús Neyra

Used 34+ times

FREE Resource

5 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

1 min • 1 pt

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Seleccione las funciones racionales propias

f(x)=5x2+3x72x+1f\left(x\right)=\frac{5x^2+3x-7}{2x+1}

f(x)=5x2+3x72x3+4x1f\left(x\right)=\frac{5x^2+3x-7}{2x^3+4x-1}

f(x)=x7x24f\left(x\right)=\frac{x-7}{x^2-4}

f(x)=2x343x+1f\left(x\right)=\frac{2x^3-4}{3x+1}

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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Determine la forma, en fracciones parciales de la función racional propia   f(x)=2x+1x22x3f\left(x\right)=\frac{2x+1}{x^2-2x-3}  

 f(x)=Ax3+Bx1f\left(x\right)=\frac{A}{x-3}+\frac{B}{x-1}  

 f(x)=Ax+3+Bx1f\left(x\right)=\frac{A}{x+3}+\frac{B}{x-1}  

 f(x)=Ax3+Bx+1f\left(x\right)=\frac{A}{x-3}+\frac{B}{x+1}  

3.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

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Determine las proposiciones correctas:

 2xx2+4dx=lnx2+4+C\int\frac{2x}{x^2+4}dx=\ln\left|x^2+4\right|+C  

 1x2+9dx=13tan1(x3)+C\int\frac{1}{x^2+9}dx=\frac{1}{3}\tan^{-1}\left(\frac{x}{3}\right)+C  

 1x3dx=lnx+3+C\int\frac{1}{x-3}dx=\ln\left|x+3\right|+C  

 1x24dx=lnx24+C\int\frac{1}{x^2-4}dx=\ln\left|x^2-4\right|+C  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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Evalúe la integral    (1x+1+2xx2+4)dx\int\left(\frac{1}{x+1}+\frac{2x}{x^2+4}\right)dx  

 lnx+1+2lnx2+4+C\ln\left|x+1\right|+2\ln\left|x^2+4\right|+C  

 lnx+1+12tan1(x2)+C\ln\left|x+1\right|+\frac{1}{2}\tan^{-1}\left(\frac{x}{2}\right)+C  

 lnx+1+lnx2+4+C\ln\left|x+1\right|+\ln\left|x^2+4\right|+C  

 lnx+1+tan1(x2)+C\ln\left|x+1\right|+\tan^{-1}\left(\frac{x}{2}\right)+C  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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Evalúe la integral    6x+7x2+25dx\int\frac{6x+7}{x^2+25}dx  

 3lnx2+25+7tan1(x5)+C3\ln\left|x^2+25\right|+7\tan^{-1}\left(\frac{x}{5}\right)+C  

 3lnx2+25+75tan1(x5)+C3\ln\left|x^2+25\right|+\frac{7}{5}\tan^{-1}\left(\frac{x}{5}\right)+C  

 2lnx2+2575tan1(x5)+C2\ln\left|x^2+25\right|-\frac{7}{5}\tan^{-1}\left(\frac{x}{5}\right)+C