sin ⁡ θ = \sin\ \theta= sin θ =

OPPOSITE SIDE to θ \theta θ /HYPOTENUSE

ADJACENT SIDE to \theta θ /HYPOTENUSE

OPPOSITE SIDE to \theta θ /ADJACENT SIDE to \theta θ

HYPOTENUSE/ OPPOSITE SIDE to \theta θ

tan ⁡ A = \tan A= tan A =

sin ⁡ A cos ⁡ A \frac{\sin A}{\cos A} cos A sin A

cos ⁡ A sin ⁡ A \frac{\cos A}{\sin A} sin A cos A

cot ⁡ A = \cot A= cot A =

cos ⁡ A sin ⁡ A \frac{\cos A}{\sin A} sin A cos A

sin ⁡ A cos ⁡ A \frac{\sin A}{\cos A} cos A sin A

cos ⁡ 30 ° = \cos30\degree= cos 3 0 ° =

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 \frac{2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2

1 3 \frac{1}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

cosec ⁡ 60 ° = \operatorname{cosec}60\degree= c o s e c 6 0 ° =

2 3 \frac{2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cot ⁡ 60 ° = \cot60\degree= cot 6 0 ° =

1 3 \frac{1}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

2 3 \frac{2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1st QUADRANT , what T-Ratio's positive?

sin ⁡ θ \sin\theta sin θ , cosec ⁡ θ \operatorname{cosec}\theta c o s e c θ

cos ⁡ θ \cos\theta cos θ , sec ⁡ θ \sec\theta sec θ

tan ⁡ θ \tan\theta tan θ , cot ⁡ θ \cot\theta cot θ

2nd QUADRANT , what T-Ratio's positive?

sin ⁡ θ \sin\theta sin θ , cosec ⁡ θ \operatorname{cosec}\theta c o s e c θ

cos ⁡ θ \cos\theta cos θ , sec ⁡ θ \sec\theta sec θ

tan ⁡ θ \tan\theta tan θ , cot ⁡ θ \cot\theta cot θ

3rd QUADRANT , what T-Ratio's positive?

tan ⁡ θ \tan\theta tan θ , cot ⁡ θ \cot\theta cot θ

sin ⁡ θ \sin\theta sin θ , cosec ⁡ θ \operatorname{cosec}\theta c o s e c θ

cos ⁡ θ \cos\theta cos θ , sec ⁡ θ \sec\theta sec θ

4th QUADRANT , what T-Ratio's positive?

cos ⁡ θ \cos\theta cos θ , sec ⁡ θ \sec\theta sec θ

sin ⁡ θ \sin\theta sin θ , cosec ⁡ θ \operatorname{cosec}\theta c o s e c θ

tan ⁡ θ \tan\theta tan θ , cot ⁡ θ \cot\theta cot θ

sin ⁡ ( − θ ) \sin\left(-\theta\right) sin ( − θ )

− sin ⁡ θ -\sin\theta − sin θ

− cosec ⁡ θ -\operatorname{cosec}\theta − c o s e c θ

cosec ⁡ ( − θ ) \operatorname{cosec}\left(-\theta\right) c o s e c ( − θ )

− cosec ⁡ θ -\operatorname{cosec}\theta − c o s e c θ

− sin ⁡ θ -\sin\theta − sin θ

sec ⁡ ( − θ ) \sec\left(-\theta\right) sec ( − θ )

− sin ⁡ θ -\sin\theta − sin θ

− cosec ⁡ θ -\operatorname{cosec}\theta − c o s e c θ

tan ⁡ ( − θ ) \tan\left(-\theta\right) tan ( − θ )

− tan ⁡ θ -\tan\theta − tan θ

− sin ⁡ θ -\sin\theta − sin θ

cot ⁡ ( − θ ) \cot\left(-\theta\right) cot ( − θ )

− cot ⁡ θ -\cot\theta − cot θ

− tan ⁡ θ -\tan\theta − tan θ

CDF 7JULY Quiz

27 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\sin\ \theta=$

OPPOSITE SIDE to $\theta$ /HYPOTENUSE

ADJACENT SIDE to $\theta$ /HYPOTENUSE

OPPOSITE SIDE to $\theta$ /ADJACENT SIDE to $\theta$

HYPOTENUSE/OPPOSITE SIDE to $\theta$

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\cos\theta=$

OPPOSITE SIDE to θ/HYPOTENUSE

ADJACENT SIDE to θ/HYPOTENUSE

OPPOSITE SIDE to θ/ADJACENT SIDE to θ

HYPOTENUSE/OPPOSITE SIDE to θ

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\tan\theta=$

OPPOSITE SIDE to θ/HYPOTENUSE

ADJACENT SIDE to θ/HYPOTENUSE

OPPOSITE SIDE to θ/ADJACENT SIDE to θ

HYPOTENUSE/OPPOSITE SIDE to θ

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\operatorname{cosec}\theta=$

HYPOTENUSE/OPPOSITE SIDE to θ

HYPOTENUSE/ADJACENT SIDE to θ

ADJACENT SIDE to θ/OPPOSITE SIDE to θ

OPPOSITE SIDE to θ/ADJACENT SIDE to θ

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\sec\theta=$

HYPOTENUSE/OPPOSITE SIDE to θ

HYPOTENUSE/ADJACENT SIDE to θ

ADJACENT SIDE to θ/OPPOSITE SIDE to θ

OPPOSITE SIDE to θ/ADJACENT SIDE to θ

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\cot\theta=$

HYPOTENUSE/OPPOSITE SIDE to θ

HYPOTENUSE/ADJACENT SIDE to θ

ADJACENT SIDE to θ/OPPOSITE SIDE to θ

OPPOSITE SIDE to θ/ADJACENT SIDE to θ

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\tan A=$

$\frac{\sin A}{\cos A}$

$\frac{\cos A}{\sin A}$

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\cot A=$

$\frac{\sin A}{\cos A}$

$\frac{\cos A}{\sin A}$

9.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If a triangle ABC is right angled at B, then $AC^2=$ _ _ _ _ _

$AB^2+BC^2$

$AD^2+DC^2$

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\sin0\degree=$

0

1

NOT DEFINED

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CDF 7JULY

sin⁡ θ=\sin\ \theta=sin θ=

cos⁡θ=\cos\theta=cosθ=

tan⁡θ=\tan\theta=tanθ=

cosec⁡θ=\operatorname{cosec}\theta=cosecθ=

sec⁡θ=\sec\theta=secθ=

cot⁡θ=\cot\theta=cotθ=

tan⁡A=\tan A=tanA=

cot⁡A=\cot A=cotA=

If a triangle ABC is right angled at B, then AC^2=AC2= _ _ _ _ _

sin⁡0°=\sin0\degree=sin0°=

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Popular Resources on Wayground

Discover more resources for Mathematics

$\sin\ \theta=$

$\cos\theta=$

$\tan\theta=$

$\operatorname{cosec}\theta=$

$\sec\theta=$

$\cot\theta=$

$\tan A=$

$\cot A=$

If a triangle ABC is right angled at B, then $AC^2=$ _ _ _ _ _

$\sin0\degree=$