IX RATIONALISING SURDS

Simplify by rationalizing the denominator:

(Hint: rewrite without a surd on the denominator)

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Tags

CCSS.HSN.RN.A.2

To rationalize the denominator of this expression you need to multiply by

• $\frac{4}{4}$

• $\frac{\sqrt{3}}{\sqrt{3}}$

• $\frac{4}{\sqrt{3}}$

• $\frac{\sqrt{3}}{4}$

Rationalize the denominator:
 $\frac{\sqrt{5}}{2\sqrt{3}}$  

•  $\frac{\sqrt{15}}{6}$  

•  $\frac{\sqrt{15}}{18}$  

•  $\frac{5\sqrt{3}}{6}$  

•  $\frac{5\sqrt{3}}{18}$  

Tags

CCSS.HSN.RN.A.2

Do you think

 $\sqrt{\left(3\right)\left(4\right)}$  is equal to  $\sqrt{3}\times\sqrt{4}$  ?

• Yes 

• No

 $surds\ \ like\ \ a+\sqrt{b\ }\ and\ a-\sqrt{b}\ are\$  

•  $like\ surds$  

•  $unlike\ surds$  

•  $conjugate\ surds$  

•  $None$  

 $Rationali\sin g\ a\ term\ \ is\ changing\ \ a\ irrational\ term\ to$  

•  $rational$  

•  $irrational$  

•  $integer$  

•  $None$  

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CCSS.8.NS.A.1

 $Identify\ the\ rationali\sin g\ factor\ of\ \frac{1}{\sqrt{8}}$  

•  $\sqrt{2}$  

•  $\sqrt{8}$  

•  $\frac{1}{2}$  

•  $\frac{1}{3}$  

 $conjugate\ term\ of\ 3+\sqrt{2}\ is$  

•  $3$  

•  $\sqrt{2}$  

•  $3-\sqrt{2}$  

•  $-\sqrt{2}$  

Tags

CCSS.HSN.CN.A.3

 $Simplify\ \sqrt{16}$  

• 2
  

• 4

• -2

• 3

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CCSS.8.EE.A.2

 $conjugate\ surd\ of\ \ 5-\sqrt{3}\$  

•  $5+\sqrt{3}$  

•  $-\sqrt{3}$  

•  $\sqrt{3}$  

•  $-5$  

Tags

CCSS.HSN.CN.A.3