การหาอนุพันธ์ของฟังก์ชัน

การหาอนุพันธ์ของฟังก์ชัน

12th Grade

10 Qs

quiz-placeholder

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การหาอนุพันธ์ของฟังก์ชัน

การหาอนุพันธ์ของฟังก์ชัน

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Hard

Created by

ประทินพร ผิวบาง

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=3x32x2+2xy=3x^3-2x^2+\frac{2}{x}  จงหา  dydx\frac{\text{d}y}{\text{d}x}  

 9x24x2x29x^2-4x-\frac{2}{x^2}  

 9x24x+2x29x^2-4x+\frac{2}{x^2}  

 9x24x2x9x^2-4x-\frac{2}{x}  

 9x32x2x29x^3-2x-\frac{2}{x^2}  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=2x325x12+x y=2x^{\frac{3}{2}}-5x^{\frac{1}{2}}+\sqrt{x}\   จงหา  dydx\frac{\text{d}y}{\text{d}x}  

 3x22x\frac{3\sqrt{x}}{2}-\frac{2}{\sqrt{x}}  

 3x2x3\sqrt{x}-\frac{2}{\sqrt{x}}  

 3x+2x3\sqrt{x}+\frac{2}{\sqrt{x}}  

 3x12x3\sqrt{x}-\frac{1}{2\sqrt{x}}  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=2x+1x+1y=\frac{2x+1}{x+1}  จงหา  dydx\frac{\text{d}y}{\text{d}x}  

 2(x+1)2\frac{2}{\left(x+1\right)^2}  

 4x+3(x+1)2\frac{4x+3}{\left(x+1\right)^2}  

 1(x+1)2\frac{1}{\left(x+1\right)^2}  

 3(x+1)2\frac{3}{\left(x+1\right)^2}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=(3x21)(4x+5 )  dydxy=\left(3x^2-1\right)\left(4x+5\ \right)\ จงหา\ \frac{\text{d}y}{\text{d}x}  

 36x2+30x+436x^2+30x+4  

 36x2+24x436x^2+24x-4  

 36x230x436x^2-30x-4  

 36x2+30x436x^2+30x-4  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=(4x2x)2   dydxy=\left(4x^2-\sqrt{x}\right)^2\ \ จงหา\ \frac{\text{d}y}{\text{d}x}  

 2(4x2x)(8x12x)2\left(4x^2-\sqrt{x}\right)\left(8x-\frac{1}{2\sqrt{x}}\right)  

 2(4x2x)(8x1x)2\left(4x^2-\sqrt{x}\right)\left(8x-\frac{1}{\sqrt{x}}\right)  

 (4x2x)(8x12x)\left(4x^2-\sqrt{x}\right)\left(8x-\frac{1}{2\sqrt{x}}\right)  

 2(4x2x)(8x+12x)2\left(4x^2-\sqrt{x}\right)\left(8x+\frac{1}{2\sqrt{x}}\right)  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

  3    y=7x45x3+4x210x+3 จงหาอนุพันธ์อันดับที่\ 3\ ของ\ \ \ y=7x^4-5x^3+4x^2-10x+3\   

 168x168x  

 168x15168x-15  

 168x30168x-30  

 168168  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=1x+1y=\frac{1}{x+1}  

จงหาอนุพันธ์อันดับที่ 2 

 1(x+1)3\frac{-1}{\left(x+1\right)^3}  

 2(x+1)3\frac{-2}{\left(x+1\right)^3}  

 2(x+1)3\frac{2}{\left(x+1\right)^3}  

 2(x+1)2\frac{2}{\left(x+1\right)^2}  

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