Surface area of a Cube and Cuboid | Surface Areas and Volumes | Assessment | English | Grade 9

Total surface area of cuboid = ________

• 2(lb + bh)

• lb + bh + hl

• 2(lb + bh + hl)

• 1/2(lb + bh + hl)

Answer explanation

Total surface area of cuboid = 2(lb + bh + hl)

Tags

CCSS.6.G.A.4

The length of a cube is 24 cm. Find the total surface area of a cube.

• 3456 cm²

• 3500 cm²

• 3656 cm²

• 3356 cm²

Answer explanation

l = 24 cm Total surface area = 6l² = 6 x 24 x 24 = 3456 cm²

Tags

CCSS.6.G.A.4

Total surface area of a cube is 384 m². Find the length of a cube.

• 10 m

• 12 m

• 6 m

• 8 m

Answer explanation

Total surface area = 6l² 384 = 6l² l² = 64 l = 8 m

Tags

CCSS.6.G.A.4

Find the total surface area of cuboid, if l = 14 m, b = 8 m and height = 6.5 m.

• 520 m²

• 510 m²

• 410 m²

• 512 m²

Answer explanation

l = 14 m, b = 8 m, h = 6.5 m Total surface area of cuboid = 2(lb + bh + hl) = 2 [(14 x 8) + (8 x 6.5) + (6.5 x 14)] = 2(112 + 52 + 91) = 510 m²

Tags

CCSS.6.G.A.4

Find the cost of painting a cubical box of length 12 cm, if 1 cm² cost ₹ 30.50.

• ₹ 26552

• ₹ 27352

• ₹ 26352

• ₹ 25352

Answer explanation

Total surface area = 6l² = 6(12)² = 864 cm² Therefore, cost of painting = 864 x 30.50 = ₹ 26352

Tags

CCSS.6.G.A.4

Find the cost of sheet required for making a cuboidal box measuring 6 m x 4.5 m x 8 m, if 1 m² cost ₹ 54.

• ₹ 11900

• ₹ 12988

• ₹ 10988

• ₹ 11988

Answer explanation

Total surface area of cuboid = 2(lb + bh + hl) = 2 [(6 x 4.5) + (4.5 x 8) + (8 x 6)] = 2(27 + 36 + 48) = 222 m² Therefore, total cost of sheet = 222 x 54 = ₹ 11988

Tags

CCSS.6.G.A.4