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22 餘式因式

Authored by Mok Wai莫達威老師

Mathematics

KG - University

Used 3+ times

22 餘式因式
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14 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

被除式,除式,商式和餘式的關係

被除式=除式×商式+餘式
被除式=除式×餘式+商式
被除式=除式×商式餘×式
被除式=除式+商式+餘式

Answer explanation

被除式7,除式3,商式2和餘式 1

7 ÷ 3 = 2 ... 1

7 = 3 × 2 + 1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以p(x) 商是 (x+1) 餘是 6,即?

f(x) = p(x) (x+1) + 6
f(x) = p(x) (x-1) + 6
f(x) = p(x) (x+1) - 6
f(x) = p(x) (x-1) - 6

Answer explanation

被除式=除式×商式+餘式

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以p(x) 商是 (x-1) 餘是 -6即?

f(x) = p(x) (x+1) + 6
f(x) = p(x) (x-1) + 6
f(x) = p(x) (x+1) - 6
f(x) = p(x) (x-1) - 6

Answer explanation

被除式=除式×商式+餘式

+(-6)=-6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以 x+1 的餘式是?

f(-1)
f(1)
f(-2)
f(-1/2)

Answer explanation

設 x+1=0

x=-1, f(-1) 是餘式

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以 x-1 的餘式是?

f(-1)
f(1)
f(-2)
f(-1/2)

Answer explanation

設 x-1=0

x=1, f(1) 是餘式

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以 2x+1 的餘式是?

f(1/2)
f(2)
f(-2)
f(-1/2)

Answer explanation

設 2x+1=0

x=-1/2, f(-1/2) 是餘式

用 f(-0.5) 也可

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) 除以 2x-1 的餘式是?

f(1/2)
f(2)
f(-2)
f(-1/2)

Answer explanation

設 2x-1=0

x=1/2, f(1/2) 是餘式

用 f(0.5) 也可

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