Bipolar Junction Transistor (BJT)

What is the operation region of NPN Bipolar Junction Transistor (BJT) if the voltage values of V_BE is 0.3V and V_BC is 0.7V?

• Saturation region

• Cut-off region

• Active region

• In-active region

What is the operation region of NPN Bipolar Junction Transistor (BJT) if the voltage values of V_BE is 0.7V and V_BC is 0.7V?

• Saturation region

• Cut-off region

• Active region

• In-active region

The circuit shown is the Bipolar Junction Transistor that works in an active region. What happen to the collector current, I_c when the value of base resistor R_B is increased?

• The I_c will remain the same.

• The I_c will be 0.

• The I_c will increase.

• The I_c will decrease.

Determine the configuration this BJT circuit.

• Common Emitter

• Common Base

• Common Collector

• Common Ground

What is the value of V_BE?

Given V_cc = +22 V, V_th = 2V, R_th = 3.55 Ω, R_c = 10 kΩ and RE = 1.5 kΩ.

• 1.978 V

• 13.5 V

• 0.7 V

• 1.275 V

What is the formula of R_th to simplify the BJT voltage divider bias circuit shown in the figure?

• (R₁ + R₁)/ (R₂ x R₂)

• (R₁ x R₁) / (R₂ + R₂)

• (R₁ x R₂)/ (R₁ + R₂)

• (R₁ + R₂)/ (R₁ x R₂)

The figure shown the fixed bias circuit of BJT. What is the CORRECT formula to calculate the value of base current, I_B?

• V_CC - I_cR_c − V_CE - V_BE - I_BR_B = 0

• V_CC + I_BR_B − V_BE = 0

• V_CC - I_BR_B − V_BE = 0

• V_CC + I_cR_c − V_CE - V_BE - I_BR_B = 0

BJT is a device controlled by (a)  

The figure shown the fixed bias circuit of BJT. What is value of base current, I_B?

• 20.28 μA

• - 20.28 mA

• 20.28 mA

• - 20.28 μA

To solve the BJT voltage divider bias AC circuit analysis, identify which statement is incorrect?

• Locate capacitors and replace them with an open circuit

• Locate resistors and replace them with an open circuit

• Simplified circuit using Thevenin Theorem

• Locate 2 main loops which is BE loop and CE loop