Penalaran Matematika UTBK 2

sepatuh seluruh bidang tanah = 500m² : 2 = 250m²

jumlah pohon yang dibutuhkan = luas tanah yang ditanami : luas tanah yang dibutuhkan perpohon

x = 250 : 5

x = 50 pohon

J= K x W

J= 60 x 5 = 300

Jarak pada peta= (300:30)x 1= 10Cm

1 + 2 + 3 + ... + 98 + 99 + 100

= 101 + 101 + 101 + ... 101

=50 x 101 = 5050

x = $$\frac{10}{8}$$  x $$\frac{6}{5}$$   x 120 = 180

$$\frac{a\ +\ b+c+7+d+d\ +9}{7}$$  = 7

= a + b + c + 7 + d + d + 9 = 7 x 7

= a + b + c + 7 + d + d + 9 =49

= a + b + c + 2d= 49 - 16 = 33

karena

a+ b+ c= 17

sehingga 17 + 2d= 33

2d = 33-17

2d = 16

d= 8

jadi nilai rata-rata terbaik =

$$\frac{8+8+9}{3}$$  = $$\frac{25}{3}$$  

Bersalaman terjadi tiap 2 orang (berpasangan)

(⁶ _{2 =} $$\frac{12!}{\left(12-2\right)!2!}$$  

= $$\frac{12!}{10!2!}$$  

= $$\frac{12\times11\times10!}{10!\ 2\times1}$$   = 66

1, 2, 1, 2, 3, 1, 2, 3, a, b

1, 2

1, 2, 3,

1, 2, 3, 4,

1, 2, 3, 4, 5

a= 4

b= 1

a-b = 4-1 = 3

180-116 = 64

3x = 64 + 23

3x = 87

x = 87:3

x= 29

2ⁿ (1+2¹+2²) = 56

= 2ⁿ .7 =56

= 2ⁿ= 56:7

= 2ⁿ= 8

= 2ⁿ=2³ = n= 3

$$\lim_{x\rightarrow2}\ \frac{\sin\ \left(x-2\right)}{x_{ }^2-3x\ +2}$$  

= $$\lim_{x\rightarrow2}\ \frac{\sin\ \left(x-2\right)}{\left(x\ -1\right)\ \left(x-2\right)}$$  

= $$\lim_{x\rightarrow2}\ \frac{1}{\left(x\ -1\right)}$$  

= $$\frac{1}{2-1}$$  =1