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  5. Calc 12 Ch 2.3 Intermediate Value Theorem

Calc 12 ch 2.3 Intermediate value theorem

Authored by Melissa Deveaux

Mathematics

12th Grade

CCSS covered

Used 1+ times

Calc 12 ch 2.3 Intermediate value theorem
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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a function f has a domain

(−∞, ∞)\left(-\infty,\ \infty\right)  , then it is _______________.

increasing

extraneous

continuous

undefined

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

For the function

f(x)=⌊x⌋f\left(x\right)=\lfloor x\rfloor  , determine an interval where f is continuous.

[0.5, 1.5]

[-1, 1]

[-2, 0]

[1, 1.5]

Tags

CCSS.HSF-IF.C.7B

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Assume f(x) is continuous over the interval [-2, 3]. The function f has at least how many zeros?

1

2

3

4

4.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Media Image

Determine the interval(s) for which the function is continuous. Select all that apply.

(p, 0)

[0, q]

[q, r]

(r, s)

(q, s)

Tags

CCSS.8.F.A.1

CCSS.HSF.IF.B.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Use the Intermediate Value Theorem to find an interval between two consecutive integers that contains a zero of the function

h(x)=2x−x2−ln⁡xh\left(x\right)=2x-x^2-\ln x  

[-1, 0]

[0, 1]

[1, 2]

(-1, 1)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Consider the function

f(x)=1x−3−5f\left(x\right)=\frac{1}{x-3}-5  .  Can you conclude that there must be a zero between f(2) and f(3.1)?

Yes, because f(2) is negative and f(3.1) is positive.

No, because f(2) is negative and f(3.1) is also negative.

Yes, because f(2) is positive and f(3.1) is negative.

No, because there is a discontinuity at x = 3.

No, because f(2) is positive and f(3.1) is also positive.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A hot apple pie is left on a window sill to cool. Suppose its temperature (degrees F) after x minutes is given by

f(x)=90e−0.61x+70f\left(x\right)=90e^{-0.61x}+70  .  Give an interval in which its temperature will first be under  100°F100\degree F  

(0, 0.5)

(0.5, 1)

(1, 1.5)

(1.5, 2)

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