Quiz about FUNGSI KUADRAT KELAS IX

Question 1

$$Grafik\ fungsi\ kuadrat\ f\left(x\right)=-3x^2+7x-2\ melalui\ titik\ ....$$

Accepted Answer

(-1,-12),(0,-2) dan (2,0)

Answer

(-1,-12),(0,-2) dan (2,4)

Answer

(-1,-12),(0,2) dan (2,0)

Answer

(-1,-12),(0,2) dan (2,0)

Question 2

$$f\left(x\right)=-2x^2-5x+12$$ grafik tsb memotong sumbu x di titik....

Accepted Answer

$$\left(1\frac{1}{2},\ 0\right)dan\ \left(-4,0\right)$$

Answer

$$\left(-1\frac{1}{2},\ 0\right)dan\ \left(-4,0\right)$$

Answer

$$\left(-1\frac{1}{2},\ 0\right)dan\ \left(4,0\right)$$

Answer

$$\left(1\frac{1}{2},\ 0\right)dan\ \left(4,0\right)$$

Question 3

$$f\left(x\right)=-x^2+4x+5$$ sumbu simetri grafik fungsi kuadrat tersebut adalah...

Accepted Answer

x=2

Answer

x=-2

Answer

x=-1

Answer

x=1

Question 4

$$f\left(x\right)=-x^2+3x+10$$ koordinat titik balik fungsi kuadrat tersebut adalah....

Accepted Answer

$$\left(\frac{3}{2},12\frac{1}{4}\right)$$

Answer

$$\left(\frac{-3}{2},9\frac{1}{4}\right)$$

Answer

$$\left(\frac{-3}{2},12\frac{1}{4}\right)$$

Answer

$$\left(\frac{3}{2},9\frac{1}{4}\right)$$

Question 5

Grafik fungsi y = -9x²+ 12x - 6 memotong sumbu y di titik ....

Accepted Answer

(0,-6)

Answer

(0,6)

Answer

(6,0)

Answer

(-6,0)

Question 6

Persamaan grafik fungsi kuadrat yang mempunyai titik balik minimum (1, 2) dan melalui titik (2, 3) adalah ...

Accepted Answer

$$y=x^2-2x+3$$

Answer

$$y=x^2-2x+1$$

Answer

$$y=x^2+2x+1$$

Answer

$$y=x^2+2x+3$$

Question 7

Grafik fungsi y = -9x²+ 12x + 6 memotong sumbu y di titik ....

Accepted Answer

(0,6)

Answer

(0,-6)

Answer

(6,0)

Answer

(-6,0)

Question 8

Sebuah fungsi kuadrat melalui titik puncak (2,0). Jika fungsi kuadrat tersebut melalui titik (0,4), maka persamaan fungsi kuadrat tersebut adalah....

Accepted Answer

f(x)=x² - 4x + 4

Answer

f(x)=x² + 4x + 4

Answer

f(x)=x² - 4x - 4

Answer

f(x)=x² + 2x + 4

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