
Konfigurasi Elektron
Authored by Nining Yumaitelia
Chemistry
10th Grade
Used 30+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
konfigurasi elektron yang tepat
2 1
1 1 1
2 0 1
1 2
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Elektron Valensi dari 35Br
5
6
7
8
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Diagram orbital dengan Nomor Atom 15
4.
FILL IN THE BLANK QUESTION
1 min • 1 pt
Bilangan kuantum adalah Bilangan yang menyatakan kedudukan atau posisi elektron dalam atom. Sebutkan 4 bilangan kuantum tersebut
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Dengan menggunakan konfigurasi gas mulia, tuliskan konfigurasi elektron singkat dari unsur-unsur dengan nomor atom 25
[Ne] 3s2 3p6 3d5
[Ar] 4s2 3d5
[He] 4s2 3d5
[Kr] 4s2 3d5
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Tentukan bilangan kuantum elektron terakhir dari atom 15P
n = 3 (kulit ke-3)
ℓ = 0 (subkulit s)
m = +1 (nomor orbital = +1)
s = + 1 /2 (elektron ke arah atas
n = 3 (kulit ke-3)
ℓ = 1 (subkulit p)
m = +1 (nomor orbital = +1)
s = - 1 /2 (elektron ke arah atas
n = 3 (kulit ke-3)
ℓ = 1 (subkulit p)
m = +1 (nomor orbital = +1)
s = + 1 /2 (elektron ke arah atas
n = 3 (kulit ke-3)
ℓ = 2 (subkulit d)
m = +1 (nomor orbital = +1)
s = + 1 /2 (elektron ke arah atas
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Tentukan bilangan kuantum elektron terakhir dari atom 26Fe
n = 1 (kulit ke-1)
ℓ = 2 (subkulit d)
m = -2 (nomor orbital = -2)
s = - 1 /2 (elektron ke arah bawah)
n = 3 (kulit ke-3)
ℓ = 1 (subkulit p)
m = -2 (nomor orbital = -2)
s = - 1 /2 (elektron ke arah bawah
n = 3 (kulit ke-3)
ℓ = 2 (subkulit d)
m = -1 (nomor orbital = -2)
s = - 1 /2 (elektron ke arah bawah
n = 3 (kulit ke-3)
ℓ = 2 (subkulit d)
m = -2 (nomor orbital = -2)
s = - 1 /2 (elektron ke arah bawah)
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