ôn tập giữa kì 2

$$2018^x\ln2018$$

$$\frac{2018^{x+1}}{x+1}$$

$$\frac{x2018^{x-1}}{\ln2018}$$

$$\frac{2018^x}{\ln2018}$$

$$e^x-\sin x+C$$

$$\frac{1}{x+1}e^{x+1}+\sin x+C$$

$$xe^{x-1}-\sin x+C$$

$$e^x+\sin x+C$$

$$\frac{a^x}{\ln a}$$

$$a^x+C$$

$$a^x\ln a+C$$

$$e^x+C$$

$$F\left(x\right)=\frac{x^2}{2}+\frac{3^x}{\ln3}+C$$

$$F\left(x\right)=1+\frac{3^x}{\ln}+C$$

$$F\left(x\right)=\frac{x^2}{2}+3^x+C$$

$$F\left(x\right)=\frac{x^2}{2}+3^x\ln3+C$$

$$\int kf\left(x\right)dx=k\int f\left(x\right)dx$$

$$\int kf\left(x\right)dx=\frac{1}{k}\int f\left(x\right)dx$$

$$\int kf\left(x\right)dx=kf\left(x\right)$$

$$\int kf\left(x\right)dx=k+\int f\left(x\right)dx$$

$$uv-\int vdu$$

$$uv-\int udv$$

$$uv+\int vdu$$

$$uv+\int udv$$

$$\int_1^3f\left(x\right)dx=F\left(3\right)-F\left(1\right)$$

$$\int_1^3f\left(x\right)dx=F\left(1\right)-F\left(3\right)$$

$$\int_1^3f\left(x\right)dx=F\left(3\right)+F\left(1\right)$$

$$\int_1^3f\left(x\right)dx=\int_3^1f\left(x\right)dx$$

$$\int_{ }^{ }e^xdx=e^x+C$$

$$\int x^3dx=\frac{x^4}{4}+C$$

$$\int\frac{1}{x}dx=\ln\left|x\right|+C$$

$$\int\sin3xdx=\frac{1}{3}\cos3x+C$$

$$\int x^edx=\frac{x^{e+1}}{e+1}$$

$$\int x^edx=\frac{x^{e+1}}{x+1}$$

$$\int\frac{1}{x}dx=\ln\left|x\right|+C$$

$$\int\cos2xdx=\frac{1}{2}\sin2x+C$$

$$f\left(b\right)-f\left(a\right)$$

$$f\left(b\right)+f\left(a\right)$$

$$f\left(a\right)-f\left(b\right)$$

$$b-a$$