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Unit 3 Review-Parallel Lines and Transversals

Authored by LaShanda Coward

Mathematics

10th Grade

CCSS covered

Used 6+ times

Unit 3 Review-Parallel Lines and Transversals
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18 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the slope of the line?

5

-5

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0

Tags

CCSS.8.EE.B.5

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the line that passes though the point (4, -3) and has slope of 3?

y = 3x - 7

y= 3x - 15

y = 3x - 7

y = 3x + 7

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation represents the line that passes through points

(2, 0) and (-2, 4)?

y = -x + 2

y = x - 2

y = 4x + 2

y = 2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Two points are shown on the line in the graph. What is the equation of the line?

y = 2x - 2

y = 1/2 x + 2

y = 2x + 1

y = 2x + 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What are the coordinates of the midpoint of the segment?

(1, 2)

(3, 2)

(-1, 4)

(-1, 2)

Tags

CCSS.HSG.GPE.B.6

6.

OPEN ENDED QUESTION

3 mins • 2 pts

Media Image

Use the angle relationship in the figure to solve for x. Assume that the lines are parallel with a transversal and the given angles are given in degrees.

x = ?

Make sure you type your answer using "x = "

Evaluate responses using AI:

OFF

Tags

CCSS.8.G.A.5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Two parallel lines are cut by a transversal, as shown. What is the solution for x, and why?

x = 17. because corresponding angles are equal.

Therefore 3y + 53 = 7y - 55

x = 27, because alternate exterior angles are equal.

Therefore 3y + 53 = 7y - 55

x = 22, because interior angles are equal..

Therefore 3y + 53 = 7y - 55

x = 24, because vertical angles are equal.

Therefore 3y + 53 = 7y - 55

Tags

CCSS.8.G.A.5

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