Writing the equation of a straight line

Find the equation of the line:
(0, 2) and (-1, -2)

• y = -2x + 2
• y = 4x + 2
• y = 2x - 4
• y = -4x + 2

Which is the equation of the line that passes through the points (-4, 8) and (1, 3)?

• y = -x+ 4

• y = -x+ 12

• y = x+ 4

• y = x+ 12

Tags

HSA.CED.A.2

HSA.SSE.A.1

HSS.ID.C.7

HSA.CED.A.3

HSA.REI.D.10

Write the equation of the line in slope-intercept form

• 
  

  $y=\frac{3}{2}x-6$
  

• $y=3x-7$

• $y=-\frac{3}{2}x+6$

• $y=\frac{2}{3}x-6$

Find the equation of the line that passes through the points (-2, 3) and (-1, 7)

• 
  

  $y=\frac{1}{4}x+2$

• y = -4x - 5

• y = 4x + 5

• y = 4x + 11

Find the mistake. 

• They got the wrong slope. 
• They chose the wrong y-intercept. 
• They plugged in their values incorrectly. 
• They simplified wrong. 

Find the equation of the line in slope-intercept form. 

Write the equation of the line through (0, 3) and (-2, 0)

• y = 3x + 3/2

• 
  

  $y=\frac{1}{3}x$
  

• $y=\frac{1}{2}x$
  

• y = 2x -1
  

• y =2x + 1
  

Find the slope and y-intercept of the two points to formulate an equation in slope-intercept form.

(20, 14), (12, 15)

• y = 2/5 x +6

• y= 2/5 x + 7

• y= -2/5 x +22

• y = -2/5 x +8

Find the equation of the straight line through the points (-1, 3) and (1, 6).

• -3x+2y=9
• x=-1
• x=1
• 3x-2y=9