Dividing Polynomials by Binomials Using Synthetic Division

Dividing Polynomials by Binomials Using Synthetic Division

10th - 12th Grade

23 Qs

quiz-placeholder

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Dividing Polynomials by Binomials Using Synthetic Division

Dividing Polynomials by Binomials Using Synthetic Division

Assessment

Quiz

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
HSA.APR.D.6, HSA.APR.B.2

Standards-aligned

Created by

Barbara White

FREE Resource

23 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What does this tell me?

f(-2)= -27 and -27 is the remainder

-2 is a solution of the function

(x+2) is a factor of the function

(x-2) is a factor of the function

Tags

CCSS.HSA.APR.D.6

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How can I tell, when doing synthetic division, if the binomial is a FACTOR of the dividend?

The remainder is zero

They are all factors

We can't tell

The remainder is a constant

Tags

CCSS.HSA.APR.D.6

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If x-2 is a factor of x^2+5x+7, then that means.....

f(0) = 2

f(0) = -2

f(2) = 0

f(-2) = 0

Tags

CCSS.HSA.APR.B.2

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

When can we use Synthetic Division to divide polynomials?

Any time we need to divide.

When dividing by a binomial

When dividing by a trinomial

Tags

CCSS.HSA.APR.D.6

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What should be the order of the polynomial coefficients if
(3x - 4x3 + 6x4 + 1) / (x + 3)
3   0   -4   6   1
6   -4   3   1   0
6   -4   0   3   1
-6   4   0   -3   -1

Tags

CCSS.HSA.APR.D.6

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

For synthetic division, what would be the number in the left hand box?

0

1

2

3

Tags

CCSS.HSA.APR.D.6

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

            Is (x-2) a factor of             f(x)= x3-8x2+14x-4?
Yes, (x-2) is a factor. There is a remainder.
No, (x-2) is  not a factor. The remainder is zero.
Yes, (x-2) is a factor. The remainder is zero.
No, (x-2) is  not a factor. There is a remainder. 

Tags

CCSS.HSA.APR.B.2

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