Convert Circle Equations into Center Radius Form

What is the radius of the given circle:
 x²+y²-10x+8y-23=0?

• 4
• 2
• 8

Tags

CCSS.HSG.GPE.A.1

Determine the center and radius: x² + y² + 14x - 2y = -1

• center= (-7,2) radius= 3
• center= (-7,1) radius= 7
• center= (-4,1) radius= 5

Tags

CCSS.HSG.GPE.A.1

The general form of a circle is
x² + y² - Cx + Dy + E = 1

• True 
• False

Tags

CCSS.HSG.GPE.A.1

Determine the center and radius:
x² + y² - 10x + 8y -8 = 0

• C = (5,-4) r = 7
• C = (-5,4) r = 7
• C = (-4,5) r = 49
• C = (5,-4) r = 49

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form:
x² + y² + 4x + 6y - 36 = 0

• (x+2)² + (y+3)² = 49
• (x+2)² + (y+3)² = 13
• (x-2)² + (y-3)² = 49
• (x-2)² + (y-3)² = 13

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25
• (x+3)² + (y-6)² = 25
• (x-3)² + (y+6)² = 45
• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

Determine the equation of a circle with center (5,-3) and radius of 9

• x²+y²-10x+6y-47=4
• x²+y²-10x-6y-47=0
• 2x²+y²+10x+6y-47=0
• x²+y²-10x+6y-47=0

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)
• (4, 3)
• (-4, -3)
• (3, 4)

Tags

CCSS.HSG.GPE.A.1