Solving Factored Quadratics

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.
-4y² + 24y - 36 = 0

• -3

• 7/2

• 4

• 3

Tags

CCSS.HSA-REI.B.4B

Find the expression equivalent to (x-1)(x-9)

• x²+9

• x²-10x+9

• x²-10x-9

• x²+10x+9

Tags

CCSS.HSA.APR.A.1

Solve
(4a + 3)(4a - 3) = 0

• a = ^-3/₄, ³/₄ 

• a = ^-4/₃, ⁴/₃ 

• a = ^-9/₁₆, ⁹/₁₆ 

• a = ^-16/₉, ¹⁶/₉ 

Tags

CCSS.HSA-REI.B.4B

Convert x²-9x+20 to factored form and solve.

• (x-10)(x+2); x=-2, 10

• (x+4)(x+5); x=-5, -4

• (x-4)(x-5); x=4, 5

• Not factorable

Tags

CCSS.HSA-REI.B.4B

Solve by factoring

• A

• B

• C

• D

Tags

CCSS.HSA-REI.B.4B

solve:  
4x²+16x+15=0

• -5/2,-3/2

• (2x+5)(2x+3)

• -10,-6

• 5/2, 3/2

Tags

CCSS.HSA-REI.B.4B

Solve in any method

• A

• B

• C

• D

Tags

CCSS.HSA-REI.B.4B

y = 2x^2 -x -3 factors into

• (2x+3)(x-1)

• (2x-3)(x-1)

• (2x-3)(x+1)

• (2x+3)(x+1)

Solve by factoring!

• -2, 4

• -8

• ±8

• No real solution

Tags

CCSS.HSA-REI.B.4B