Bisects

Bisects

10th Grade

20 Qs

quiz-placeholder

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Bisects

Bisects

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Hard

CCSS
HSG.CO.C.9, HSG.SRT.B.5, 7.G.B.5

+2

Standards-aligned

Created by

Anthony Clark

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

x=67
x=43
x=55
x=12

Tags

CCSS.7.G.B.5

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

It divides or bisects a segment into two congruent segments; the point in the middle of the segment.

point

midpoint

line

bisector

Tags

CCSS.HSG.CO.A.1

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

m<EFJ = 90, m<JFG = 90

m<EFJ = 45 m<JFG = 45

m<EFJ = 180, m<JFG = 180

m<EFJ = 45 m<JFG = 90

Tags

CCSS.7.G.B.5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the value of x?

10.667

11.333

42

10

Tags

CCSS.HSG.CO.C.9

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What does it mean to bisect a segment or an angle?

Split it into 3 equal parts.

Split it into 2 equal parts.

Split into 4 equal parts.

Double it.

Tags

CCSS.HSG.CO.C.9

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
What is the justification for Step 4?

Given

Substitution

Angle addition postulate

Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
What is the justification for Step 6?

Subtraction property of equality

Substitution

Addition property of equality

Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

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