Angle Bisector Theorem Similar Triangles

The angle-bisector theorem can be applied in

• isosceles triangles only

• any type of triangle

• right-angled triangles

• equilateral triangles only

Tags

CCSS.HSG.CO.C.9

What will the last "reason" of this proof be?

• Definition of Midpoint

• Definition of Angle Bisector

• CPCTC

• Reflexive

Tags

CCSS.HSG.CO.C.9

In similar triangles, corresponding angles are ___________.

• similar

• congruent

• overlapping

• proportional

Tags

CCSS.HSG.SRT.A.2

Find the length of TU

• 15

• 12

• 26

• 13

Tags

CCSS.HSG.C.A.3

Which of the following below would fill in the Reasons in the proper order?

• Given; Definition of bisect; Transitive; Given, Definition of bisect

• Given; Transitive; Given; Definition of bisect; Definition of bisect

• Given; Definition of bisect; Given; Definition of bisect; Transitive

Tags

CCSS.HSG.CO.C.9

What is the missing statement in the proof?

• 2m∠ABD = m∠ABD + m∠ABD

• m∠ABD = m∠DBC

• m∠ABC = m∠ABC

• m∠ABD +m∠ABD = m∠ABD + m∠DBC

Tags

CCSS.HSG.SRT.B.5

What is the missing statement in the proof?

• 2m∠ABD=m∠ABD+m∠ABD

• m∠ABD=m∠DBC

• m∠ABC=m∠ABC

• m∠ABD+m∠ABD=m∠ABD+m∠DBC

Tags

CCSS.8.G.A.5

What is reason 2?

• 
• 
• 
• 

Tags

CCSS.HSG.CO.C.9

What is reason #2?

• Definition of Midpoint

• Definition of Perpendicular

• Definition of Angle Bisector

• Definition of Right Triangle

Tags

CCSS.HSG.SRT.B.5

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
What is the justification for Step 4?

• Given

• Substitution

• Angle addition postulate

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5