Angle Bisector, Altitude, Median

Angle Bisector, Altitude, Median

10th Grade

20 Qs

quiz-placeholder

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Angle Bisector, Altitude, Median

Angle Bisector, Altitude, Median

Assessment

Quiz

Mathematics

10th Grade

Hard

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The figure is an example of a(n) ...

angle bisector

perpendicular bisector

median

midsegment

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which of the following segments represents an altitude?

BX

AZ

AC

BZ

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The dotted line represents a ?...

median

centroid

midsegment

midpoint

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which of the following segments represents a median?

BX

AZ

AC

BZ

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: PL is the angle bisector of <RPQ
What can you conclude by definition of angle bisector?

m<RPL = m<LPQ

<RPL + m<LPQ = m<RPQ

<RPQ is acute

m<RPQ = 90

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
What is the justification for Step 7?

Subtraction property of equality

Transitive property of equality

Addition property of equality

Definition of congruent angles

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?

Symmetric property of congruence

Definition of angle bisector

Addition property of equality

Definition of congruent angles

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