Rewrite Log and Exponential Equations

log(x) + log(x+3) = 1

• 5

• -2

• -5

• 2

Solve:

log₉(x)+log₉(x+2)=log₉(35)

• 5

• -7

• 5, -7

• -7, -13

log (x - 1) - log (x - 2) = log 5

• 7

• 4/9

• 9/4

• 1/7

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined

Rewrite the exponential as a log.

2^3x+1 = 12

• ln(2)= 3x+1

• log₂(12)= 3x+1

• ln(6)=3x+1

• log₁₂(2)= 3x+1

2log₆(x-8)=2

• 14

• 81/8

• 18

• 9969

ln(x+8) - ln (8) = 3

• 152.68

• 188.77

• 4.24

• 8.01

Determine the correct set-up for: log₄(x-1) - log₄(x+7) = log₄6

• log₄(x-1)/(x+7)=log₄(6)

• log₄(x-1)(x+7)=log₄(6)

• log₄(x+7)/(x-1)=log₄(6)

• (x-1)(x+7)=6

Rewrite log_pt = m in exponential form.

• p^t = m

• t^m = p

• m^t = p

• p^m = t

Write the exponential equation as a logarithm
6³=216

• log₆(3) = 216

• log₃(6) = 216

• log₆(216)=3

• log₂₁₆(6)=3