Solving High Order Polynomial Equations

Find all zeros of the polynomial function P(x) = x³+6x²+9x+54

• 6, 3, -3

• -6, 3, -3

• -6, 3i, -3i

• 6, 3i, -3i

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }

•  { 1/2, 4 }

• { 2, -4 }

• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

What are two solutions to the polynomial:
x²+14x=0

• x=0, x= 14

• x=-14

• x= 1, x =10

• x= -14, x = 0 

Tags

CCSS.HSA-REI.B.4B

Solve: 2x²-14x+24 = 0

• x = 4, 3

• x = 9/2, 10/4

• x = -3, -4

• x = -9/2, -10/4

Tags

CCSS.HSA-REI.B.4B

Solve

x² + 2x - 20 = 4

• x = -6, x = 4

• x = 6, x = -4

• x = 12, x = -2

• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring:3x² + 5x + 2 = 0  

• x = -2/3 and x = -1

• x = -3/2 and x = -1

• x = 2/3 and x = 1

• x = 2/3 and x = -1

Tags

CCSS.HSA-REI.B.4B

Solve
16a² - 9 = 0

• a = ^-3/₄, ³/₄ 

• a = ^-4/₃, ⁴/₃ 

• a = ^-9/₁₆, ⁹/₁₆ 

• a = ^-16/₉, ¹⁶/₉ 

Tags

CCSS.HSA-REI.B.4B

Solve: 14m²-12m = 0

• m=2 and m=76

• m=2 and m=0

• m=14 and m=12

• m=0 and m=6/7

Tags

CCSS.HSA-REI.B.4B

Factor:   x³ + 1

• (x + 1)³

• (x+1)(x² - x + 1)

• (x - 1) (x² + x - 1)

• (x + 1)(x² - 2x + 1)

Tags

CCSS.HSA.APR.C.4

Find all the real zeros of the function
f(x) = 2x³ - 19x² + 38x + 24 given that x-4 is a factor.

• x = 1/2, -6

• x = -1/2, 6

• x = 4, -1/2, 6

• x = -4, 1/2, -6

Tags

CCSS.HSA.APR.B.2