What has to be done first here to begin to solve?

• make the equation = 0

• combine 11x and 28

• list factors of -28

• list factors of 11

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }

•  { 1/2, 4 }

• { 2, -4 }

• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

Solve for x by factoring.

• -6, -2

• -2, 6

• 2, 6

• -6, 2

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² - 5x + 6 = 0
Put the solutions in order from least to greatest.

{​ (a)   ,​ (b)   }

• -6

• 3

• 6

• -3

• 9

• -2

• -9

• 2

• 18

• -1

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

Tags

CCSS.HSA-REI.B.4B

Solve by factoring!

• -2, 4

• -8

• ±8

• No real solution

Tags

CCSS.HSA-REI.B.4B

Which answer choice correctly shows the quadratic equation above in factored form?

• (x + 7)(x - 2) = 0

• (x - 7)(x + 2) = 0

• (x - 7)(x - 2) = 0

• (x + 7)(x + 2) = 0

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² + 3x - 18 = 0
Put the solutions in order from least to greatest.

{​ (a)   ,​ (b)   }

• -6

• 3

• 6

• -3

• 9

• -2

• -9

• 2

• 18

• -1

Tags

CCSS.HSA-REI.B.4B

Solving the equation f(x) = x² - 8x + 15 =0, what are the two factors we can create to solve this equation? ​ (a)   .

• (x - 3) and (x - 5)

• (x + 3) and (x + 5)

• (x - 15)

Tags

CCSS.HSA-REI.B.4B

Solve for r:

• -3, 4

• 3, 4

• -4, -3

• -3

Tags

CCSS.HSA-REI.B.4B