Circle Equations Using Diameter Endpoints

What is the equation of a circle whose diameter is 24 and whose center is at the origin?

• x²+y²=125

• x²+y²=64

• x²+y²=144

• x²+y²=576

Tags

CCSS.HSG.GPE.A.1

Write the equation of this circle in standard form. Then sketch it labeling the center and endpoints of the horizontal and vertical diameters using exact coordinates. -6y +x^2 +y^2 +18x-10=100

Tags

CCSS.HSG.GPE.A.1

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (−3,1) and (9,6).Find the equation of the circle? Hint: In this problem, we are not given the center or radius however we can find the length of the diameter using the distance formula (Phythagoras) and then divide it by 2. The center is simply the midpoint of the given points.

• (x−5)²+(y−7/2)²=169/4

• (x−3)²+(y−3)²=169/4

• (x−3)²+(y−7/2)²=169/4

• (x−7/2)²+(y−7/2)²=169/4

Tags

CCSS.HSG.GPE.A.1

• (x-2)²+y²=234

• (x+2)²+y²=234

• (x-2)²+(y+3)²=225

• (x+2)²+(y-3)²=225

• (x-15)²+(y+3)²=4

Tags

CCSS.HSG.GPE.A.1

Find the equation of a circle who's diameter has the endpoints (18, -13) and (4, -3)

Tags

CCSS.HSG.GPE.A.1

What is the equation for the circle, if it has diameter endpoints at (3,-4) and (-5,-4)?

• (x+1)² + (y+4)² = 16

• (x+1)² + (y-4)² = 16

• (x-1)² + (y-4)² = 16

• (x+1)² + (y+4)² = 16

Tags

CCSS.HSG.GPE.A.1

Which is the equation of a circle given endpoints of the diameter are (0,5) (2,3)

• (x - 1)² + (y - 4)² = 2

• (x - 1)² + (y - 4)² = 4

• (x + 1)² + (y + 4)² = 1

• (x + 1)² + (y - 4)² = 4

Tags

CCSS.HSG.GPE.A.1

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

What is the equation for the circle, if it has diameter endpoints at (3,-4) and (-5,-4)? (Hint: first find the center, then use center and either point to find radius)

• (x+1)² + (y-4)² = 4

• (x+1)² + (y+4)² = 16

• (x-1)² + (y-4)² = 16

• (x+1)² + (y+4)² = 4

Tags

CCSS.HSG.GPE.A.1