Parabola Vertex Directrix

What is the equation of this parabola?

• (y-1)² = -4(x-3)

• (y-1)²= 4(x+3)

• (y+1)² = 4(x-3)

• (y+1)² = -4(x+3)

The 'p' value represents the distance between the vertex and the focus AND the vertex and the directrix.

• True

• False

The sign of the 'p' value determines if the graph opens upward or downward.

• True

• False

Tags

CCSS.HSG.SRT.C.8

The vertex, (h, k), is halfway between the focus and the directrix.

• true

• false

If the directrix is y = 4 and the focus is at 
(3, 0), the equation of the parabola is:

• y = (-1/8)(x - 3)² + 2

• x = (-1/8)(y - 2)² + 3

• y = (1/8)(x - 3)² + 2

• x = (1/8)(y - 2)² + 3

Find the standard form of the equation of the parabola whose focus (0, 4) and a directrix y=-4.

• y = (1/16)x²

• y² = 4x

• y² = 16x

• y = (1/4)x²

Tags

CCSS.HSG.GPE.A.2

Use the distance formula to write the equation in standard form given the focus is (0,3) and the directrix is at y=5.

• y=(-1/4)x² +3 

• y= (1/8)x²+3

• y= (-1/4)x²+4

• y=-(1/8)x² +4

Tags

CCSS.HSG.GPE.A.2

Given this directrix and vertex, what would the equation of the parabola be?

• (y-2)² = 12(x-1)

• (y-2)² = 6(x-1)

• (x-1)² = 12(y-2)

• (x-1)² = 6(y-2)

Which direction does this parabola open?

• Up

• Down

• Left

• Right