One or Two Step Tables and Equations

Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let x represent the price per pound for grapefruit, and let y represent the price per pound for oranges. Choose the system of equations that models the situation.

• 2x + 3y = 7.20

  2x + 4y = 8.80

• 3x + 2y = 7.20

  4x + 2y = 8.80

• 2x + 3y = 7.20

  4x + 2y = 8.80

• 2x + 3y = 8.80

  4x + 2y = 7.20

Tags

CCSS.8.EE.C.8C

Which of the following gives a valid reason for using the given solution method to solve the system of equations shown?

• Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

• Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

• Substitution; equation I can be solved for x in one step by dividing both

  sides by 4.

• Substitution; equation II can be solved for x in one step by subtracting 3y

  from both sides.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Tickets to a play cost $4 in advance and $5 at the door. The theater club wants to raise at least $400 from the ticket sales. If the club sells 40 tickets in advance, what is the least number they need to sell at the door to reach their goal?

Mathematical Equivalence

ON

What is the solution for x + 9 = 21

• 10

• 12

• 11

• 13

Tags

CCSS.6.EE.B.7

m+13=21

• m=34

• m=8

• m=273

• m=6

Tags

CCSS.6.EE.B.7

Solve for y:
y - 7 = 10

• 17

• -3

• 3

• -17

Tags

CCSS.6.EE.B.7

k+8=15

• k=23

• k=10

• k=7

• k=11

Tags

CCSS.6.EE.B.7

7 + g = 11

• g = 4

• g = -4

• g = 18

• g = -18

Tags

CCSS.6.EE.B.7

Solve for z in the following equation:

z - 33 = 147

• z= 114

• z = 177

• z = 180

• No Solution

Tags

CCSS.6.EE.B.7

Solve for x:

x + 19.46 = 245.3

• 264.76

• 12.6

• 50.7

• 225.84

Tags

CCSS.6.EE.B.7