Mastering the Substitution Method
Authored by Anthony Clark
Mathematics
9th Grade
CCSS covered
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20 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the system of equations by substitution.
y = -4x + 5
y = 3x - 16
(-3, -25)
(3,-7)
(11, 17)
(21, 47)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the system of equations using substitution:
-4x + 4y = 8
y = -2x - 10
(-4, -2)
(12, -34)
(4, -18)
(-2, -6)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve using substitution.
x - 2y = 2
3x + 4y = 3
(1.4, -0.3)
(3.1, 5)
(-2.5, 3.5)
(6.9, 1.02)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
solve by substitution: y=3x+14
y=-4x
y=3
y=1
y= - 2
y=4
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the system of equations using the substitution method
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the system by using the substitution method
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MATCH QUESTION
1 min • 5 pts
Read each step of the Substitution method for solving a System of Equations. Then, match the result of performing the step with the step.
(2, 1)
Step 3: Solve the equation for a value
y = 5 - 2x
Step 2: Substitute the expression in the other equation
-3x + 6(5-2x) = 0
Step 4: Substitute the variable's value in the other equation; solve
2(2) + y = 5
y = 1
Step 5: Present the solution as an ordered pair
x = 2
Step 1: Solve one equation's variable (expression)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
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