Solving Quadratics with Imaginary Roots

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What does i² =  ?

• 1

• -1

• √-1

• √1

Solve by taking the square root: -9k² = 225

• 4i

• 4, -4

• 25i, -25i

• -5i, 5i

Solve over the set of complex numbers:

2x²+18=0

• 3i²

• -3i and 3i

• 9i

• 0 and 9

What is this?

• This is the speed of light formula.

• This is the quadratic formula.

• This is the zero product property.

• This is scary.

If the discriminant is negative, then the quadratic has:

• 1 Real Solution

• 2 Real Solutions

• 2 Imaginary Solutions

If b²-4ac is negative, the quadratic equation has:

• Two real solutions

• Two imaginary solutions

• One real solution

• No solution

Solve x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2

• (5 - √15)/2  ,  (5 + √15)/2

• (5 - i√65)/2  ,  (5 + i√65)/2

• (5 - √65)/2  ,  (5 + √65)/2

Solve -2x² + 4x = 9

• (2 - i√14)/2   ,   (2 + i√14)/2

• (2 - i√-56)/2   ,   (2 + i√-56)/2

• (2 - i√-14)/2   ,   (2 + i√-14)/2

• (2 - √14)/2   ,   (2 + √14)/2

Solve for x: 

• x = {-4, -1}

• x = {-1, -4}

• x = {2+i, 2-i}

• x = {-2+i, -2-i}