Equilibrium Constants Calculations

Equilibrium Constants Calculations

11th Grade - University

8 Qs

quiz-placeholder

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Equilibrium Constants Calculations

Equilibrium Constants Calculations

Assessment

Quiz

Chemistry

11th Grade - University

Hard

NGSS
HS-PS1-7

Standards-aligned

Created by

Charles Martinez

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the equilibrium constant is much greater than one (K >> 1) then
Equilibrium is not established.
Equilibrium lies to the right (products are favored)
Equilibrium lies to the left (reactants are favored)
Neither products or reactants are favored.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the equilibrium constant is much less than one (K << 1) then
Equilibrium is not established.
Equilibrium lies to the right (products are favored)
Equilibrium lies to the left (reactants are favored)
Neither products or reactants are favored.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation Kc = Kp(RT)Δn , the Δn means
The sum of all the moles.
moles of products - moles of reactants
moles of reactants - moles of product
reaction order

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

N2O4(g) ↔ 2 NO2(g)
What is the concentration equilibrium constant expression?
K= [NO2]2/[N2O4]
K= [N2O4]/[NO2]2
K= [N2O4]2/[NO2]
K= [NO2]/[N2O4]2

Tags

NGSS.HS-PS1-7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

N2O4(g) ↔ 2 NO2(g)
What is the equilibrium constant expression?
K= (PNO2)2/ (PN2O4)
K= (PN2O4) / (PNO2)2
K= (PN2O4)/ (PNO2)
K= (PNO2) / (PN2O4)2

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

For the equilibrium
2SO3(g) ↔ 2SO2(g) + O2(g)
Kc = 4.08x10-3 at 1000K
What is Kp?
3.45 x 105
2.99
0.335
3.4 x 10-5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equilibrium-constant expression for 
CO2(g) + H2(g) ↔ CO(g) + H2O(l)
Kc= [CO][H2O] / [CO2][H2]  
Kc= [CO2][H2] / [CO]
Kc= [CO2][H2] / [CO][H2O]
Kc= [CO] / [CO2][H2]  

8.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the Kc for
2NOBr(g) + Cl2(g) ↔ 2NO(g) + 2BrCl(g)
 if 
2NOBr(g) ↔ 2NO(g) + Br2(g)
has a K= 0.014
Br2(g) + Cl2(g) ↔ 2BrCl(g)
has a K= 7.2
0.10
10
1.0 x 10-3
1.0 x 10-2