D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ !

( 1 , 8 , 11 ) \left(1,8,11\right) ( 1 , 8 , 1 1 )

( 3 , 8 , 11 ) \left(3,8,11\right) ( 3 , 8 , 1 1 )

( 3 , − 8 , 11 ) \left(3,-8,11\right) ( 3 , − 8 , 1 1 )

( 1 , − 8 , 11 ) \left(1,-8,11\right) ( 1 , − 8 , 1 1 )

( − 1 , 8 , 11 ) \left(-1,8,11\right) ( − 1 , 8 , 1 1 )

Jika p = 5 i − 4 j + 3 k p=5i-4j+3k p = 5 i − 4 j + 3 k , q = 2 i + 7 k q=2i+7k q = 2 i + 7 k , r = 6 j − 2 k r=6j-2k r = 6 j − 2 k Nilai dari p ⋅ ( q + r ) p\cdot\left(q+r\right) p ⋅ ( q + r )

D. − 38 i − 19 j + 38 k -38i-19j+38k − 3 8 i − 1 9 j + 3 8 k

A. − 38 i − 19 j − 38 k -38i-19j-38k − 3 8 i − 1 9 j − 3 8 k

B. 19 i − 39 j + 38 k 19i-39j+38k 1 9 i − 3 9 j + 3 8 k

D. 38 i + 19 j + 38 k 38i+19j+38k 3 8 i + 1 9 j + 3 8 k

E. 38 i − 39 j + 19 k 38i-39j+19k 3 8 i − 3 9 j + 1 9 k

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan\ b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗-b⃗+c⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ !

( 8 , 0 , − 4 ) \left(8,0,-4\right) ( 8 , 0 , − 4 )

( − 8 , 0 , − 4 ) \left(-8,0,-4\right) ( − 8 , 0 , − 4 )

( 6 , 0 , − 4 ) \left(6,0,-4\right) ( 6 , 0 , − 4 )

( − 6 , 0 , − 4 ) \left(-6,0,-4\right) ( − 6 , 0 , − 4 )

( 6 , 0 , 4 ) \left(6,0,4\right) ( 6 , 0 , 4 )

Diketahui vektor a ‾ = − 2 i ‾ + 5 j ‾ + 4 k ‾ \overline{a}=-2\overline{i}+5\overline{j}+4\overline{k} a = − 2 i + 5 j + 4 k dan vektor b ‾ = 4 i ‾ + 5 j ‾ + 7 k ‾ \overline{b}=4\overline{i}+5\overline{j}+7\overline{k} b = 4 i + 5 j + 7 k . Panjang proyeksi vektor a ‾ \overline{a}\ a pada vektor b ‾ \overline{b} b sama dengan ...

3 2 10 \frac{\text{3}}{\text{2}}\sqrt{10} 2 3 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 10 \frac{\text{2}}{\text{3}}\sqrt{10} 3 2 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

10 \text{}\sqrt{10} 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 10 2\sqrt{10} 2 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 10 3\sqrt{10} 3 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Diketahui vektor a ‾ = i ‾ + 2 j ‾ + x k ‾ \overline{a}=\overline{i}+2\overline{j}+x\overline{k} a = i + 2 j + x k dan vektor b ‾ = 2 i ‾ + j ‾ − k ‾ \overline{b}=2\overline{i}+\overline{j}-\overline{k} b = 2 i + j − k serta panjang proyeksi vektor a ‾ \overline{a}\ a pada vektor b ‾ \overline{b} b adalah 1 3 6 \frac{1}{3}\sqrt{6} 3 1 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> . Sudut antara vektor \overline{a}\ a dan vektor \overline{b} b adalah α \alpha α , maka cos ⁡ α \cos\ \alpha cos α =...

1 9 6 \frac{1}{9}\sqrt{6} 9 1 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 6 6 \frac{\text{1}}{\text{6}}\sqrt{6} 6 1 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 6 6 \frac{\text{3}}{\text{6}}\sqrt{6} 6 3 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 9 6 \frac{2}{9}\sqrt{6} 9 2 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 6 \frac{1}{3}\sqrt{6} 3 1 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Diketahui vektor a ‾ = 4 i ‾ − 2 j ‾ + 2 k ‾ \overline{a}=4\overline{i}-2\overline{j}+2\overline{k} a = 4 i − 2 j + 2 k dan vektor b ‾ = 2 i ‾ − 6 j ‾ + 4 k ‾ \overline{b}=2\overline{i}-6\overline{j}+4\overline{k} b = 2 i − 6 j + 4 k . Proyeksi vektor ortogonal vektor a ‾ \overline{a} a pada vektor b ‾ \overline{b} b adalah...

i ‾ − 3 j ‾ + 2 k ‾ \overline{i}-3\overline{j}+2\overline{k} i − 3 j + 2 k

i ‾ − j ‾ + k ‾ \overline{i}-\overline{j}+\overline{k} i − j + k

i ‾ − 4 j ‾ + 4 k ‾ \overline{i}-4\overline{j}+4\overline{k} i − 4 j + 4 k

2 i ‾ − j ‾ + k ‾ 2\overline{i}-\overline{j}+\overline{k} 2 i − j + k

6 i ‾ − 8 j ‾ + 6 k ‾ 6\overline{i}-8\overline{j}+6\overline{k} 6 i − 8 j + 6 k

Panjang proyeksi vektor a ‾ = 2 i ‾ + y j ‾ + k ‾ \overline{a}=2\overline{i}+y\overline{j}+\overline{k} a = 2 i + y j + k pada b ‾ = 2 i ‾ + 2 j ‾ + k ‾ \overline{b}=2\overline{i}+2\overline{j}+\overline{k} b = 2 i + 2 j + k sama dengan setengah kali panjang vektor b ‾ \overline{b} b . Dengan demikian vektor proyeksi vektor b ‾ \overline{b} b pada a ‾ \overline{a} a adalah...

16 9 i ‾ − 2 9 j ‾ + 8 9 k ‾ \frac{16}{9}\overline{i}-\frac{2}{9}\overline{j}+\frac{8}{9}\overline{k} 9 1 6 i − 9 2 j + 9 8 k

2 i ‾ + 2 j ‾ + k ‾ 2\overline{i}+2\overline{j}+\overline{k} 2 i + 2 j + k

1 2 i ‾ + 1 2 j ‾ + 1 4 k ‾ \frac{1}{2}\overline{i}+\frac{1}{2}\overline{j}+\frac{1}{4}\overline{k} 2 1 i + 2 1 j + 4 1 k

i ‾ + j ‾ + 1 2 k ‾ \overline{i}+\overline{j}+\frac{1}{2}\overline{k} i + j + 2 1 k

1 3 i ‾ + 1 3 j ‾ + 1 6 k ‾ \frac{1}{3}\overline{i}+\frac{1}{3}\overline{j}+\frac{1}{6}\overline{k} 3 1 i + 3 1 j + 6 1 k

Diketahui u → = ( 3 − 5 ) \overrightarrow{u}=\left(3\ \ \ \ \ \ \ -5\right) u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 − 5 ) dan v → = ( 4 1 ) \overrightarrow{v}=\left(4\ \ \ \ \ \ \ \ \ 1\right) v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 4 1 ) . Proyeksi vektor ortogonal ( 2 u → + v → ) \left(2\overrightarrow{u}+\overrightarrow{v}\right) ( 2 u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ) pada ( u → − 2 v → ) \left(\overrightarrow{u}-2\overrightarrow{v}\right)_{ } ( u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − 2 v <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ) adalah ...

− 13 74 ( 5 7 ) -\frac{13}{74}\left(5\ \ \ \ \ \ \ \ 7\right) − 7 4 1 3 ( 5 7 )

13 74 ( 5 7 ) \frac{13}{74}\left(5\ \ \ \ \ \ \ 7\right) 7 4 1 3 ( 5 7 )

13 74 ( − 5 7 ) \frac{13}{74}\left(-5\ \ \ \ \ \ \ 7\right) 7 4 1 3 ( − 5 7 )

13 74 ( − 5 7 ) \frac{13}{\sqrt{74}}\left(-5\ \ \ \ \ \ \ 7\right) 7 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 3 ( − 5 7 )

− 13 74 ( − 5 7 ) -\frac{13}{\sqrt{74}}\left(-5\ \ \ \ \ \ \ \ 7\right) − 7 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 3 ( − 5 7 )

LATIHAN VEKTOR XI

Authored by Riza Asfa

Mathematics

11th Grade

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

25 questions

Show all answers

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

panjang vektor $\overrightarrow{a\ }=-10i+24j$ adalah……

MULTIPLE CHOICE QUESTION

2 mins • 12 pts

$Diketahui\ a⃗=2i+5j+4k$
$b⃗=-i+3j+7k\ dan$
$c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!$

$\left(3,8,11\right)$

$\left(3,-8,11\right)$

$\left(1,-8,11\right)$

$\left(-1,8,11\right)$

$\left(1,8,11\right)$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

$Diketahui\ a⃗=i+2j+2k,$ $b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!$

$-9$

$9$

$1$

$-1$

$-6$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

|a| = 11

|a| = 13

|a| = 15

|a| = 17

|a| = 19

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

-i + 9j

11i + 5j

-11i + 9j

5i + 11j

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Diketahui\ a⃗=i+2j+k,$
$b⃗=i-2j-k.\ Tentukan\ a⃗.b⃗!$

$-6$

$-4$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diketahui titik A(8, -3) dan titik B(2, 3) titik P membagi ruas garis AB dengan perbandingan 2 : 1, koordinat titik P adalah ….

$\left(2,2\right)$

$\left(4,1\right)$

$\left(3,2\right)$

$\left(-4,-1\right)$

$\left(-4,1\right)$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika $p=5i-4j+3k$ , $q=2i+7k$ , $r=6j-2k$
Nilai dari $p\cdot\left(q+r\right)$

A. $-38i-19j-38k$

B. $19i-39j+38k$

D. $38i+19j+38k$

D. $-38i-19j+38k$

E. $38i-39j+19k$

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

20 questions

Me divierto con las Matemáticas LILEGRE 8° y 9° 2020.

Quiz

•

1st Grade - University

20 questions

Thử thách Toán Tuần 11

Quiz

•

5th Grade - University

21 questions

Funciones

Quiz

•

11th Grade

20 questions

General Mathematics - Simple and Compound Interest

Quiz

•

University

20 questions

STS Matematika Kelas X.8

Quiz

•

10th Grade - University

20 questions

Matriks 1DVM

Quiz

•

7th - 12th Grade

20 questions

Kuis Kaidah Pencacahan

Quiz

•

12th Grade

20 questions

BÀI TẬP ÔN TẬP GIỚI HẠN HÀM SỐ

Quiz

•

11th Grade

Popular Resources on Wayground

15 questions

Fractions on a Number Line

Quiz

•

3rd Grade

14 questions

Boundaries & Healthy Relationships

Lesson

•

6th - 8th Grade

13 questions

SMS Cafeteria Expectations Quiz

Quiz

•

6th - 8th Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

12 questions

SMS Restroom Expectations Quiz

Quiz

•

6th - 8th Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

10 questions

Pi Day Trivia!

Quiz

•

6th - 9th Grade

Discover more resources for Mathematics

15 questions

Pi Day Trivia

Quiz

•

9th - 12th Grade

25 questions

PI Day Trivia Contest

Quiz

•

9th - 12th Grade

20 questions

Pi Day

Quiz

•

6th - 12th Grade

20 questions

Solve Polynomials and Factoring Problems

Quiz

•

9th - 12th Grade

15 questions

Exponential Growth and Decay Word Problems Practice

Quiz

•

9th - 12th Grade

15 questions

Exponential Growth and Decay

Quiz

•

10th - 11th Grade

37 questions

A.7C - Quadratic Transformations

Quiz

•

9th - 12th Grade

19 questions

DCA review - Exponent Rules

Quiz

•

9th - 12th Grade

LATIHAN VEKTOR XI

panjang vektor a →=−10i+24j\overrightarrow{a\ }=-10i+24ja =−10i+24j adalah……

Diketahui a⃗=2i+5j+4kDiketahui\ a⃗=2i+5j+4kDiketahui a⃗=2i+5j+4k b⃗=−i+3j+7k danb⃗=-i+3j+7k\ danb⃗=−i+3j+7k dan c⃗=5i−2j−k Tentukan a⃗+b⃗!c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!c⃗=5i−2j−k Tentukan a⃗+b⃗!

Diketahui a⃗=i+2j+2k,Diketahui\ a⃗=i+2j+2k,Diketahui a⃗=i+2j+2k, b⃗=−3i−j−2k. Tentukan a⃗.b⃗!b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!b⃗=−3i−j−2k. Tentukan a⃗.b⃗!

Jika vektor a = 12 i + 5 k . ﻿Maka panjang vektor a adalah ...

A = 5i + 7j , B = -6i + 2j maka B - A = ...

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

Diketahui a⃗=i+2j+k,Diketahui\ a⃗=i+2j+k,Diketahui a⃗=i+2j+k, b⃗=i−2j−k. Tentukan a⃗.b⃗!b⃗=i-2j-k.\ Tentukan\ a⃗.b⃗!b⃗=i−2j−k. Tentukan a⃗.b⃗!

Diketahui titik A(8, -3) dan titik B(2, 3) titik P membagi ruas garis AB dengan perbandingan 2 : 1, koordinat titik P adalah ….

Diketahui vektor p = 3i + 4j + mk dan vektor q = 2i - 3j + 5k . Jika perkalian vektor p.q = 4, maka nilai m adalah ...

Jika p=5i−4j+3kp=5i-4j+3kp=5i−4j+3k , q=2i+7kq=2i+7kq=2i+7k , r=6j−2kr=6j-2kr=6j−2k Nilai dari p⋅(q+r)p\cdot\left(q+r\right)p⋅(q+r)

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

panjang vektor $\overrightarrow{a\ }=-10i+24j$ adalah……

$Diketahui\ a⃗=2i+5j+4k$
$b⃗=-i+3j+7k\ dan$
$c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗!$

$Diketahui\ a⃗=i+2j+2k,$ $b⃗=-3i-j-2k.\ Tentukan\ a⃗.b⃗!$

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

$Diketahui\ a⃗=i+2j+k,$
$b⃗=i-2j-k.\ Tentukan\ a⃗.b⃗!$

Jika $p=5i-4j+3k$ , $q=2i+7k$ , $r=6j-2k$
Nilai dari $p\cdot\left(q+r\right)$