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y' = $$\ \frac{x-\sqrt{1−x^2}·\arcsin x}{x^2\sqrt{1−x^2}}$$

y' = $$\frac{(\sqrt{1−x^2}+\arcsin x)}{x}$$

y' = $$\frac{1}{x\sqrt{(}1−x^2}$$

y' = $$\frac{\arcsin x}{1}$$

y' = 0

y' = $$\frac{2}{(\sin x + \cos x)^2}$$

y' = $$\frac{2}{(\sin x−\cos x)^2}$$

$$y' = (sin x + cos x)^2 + (sin x − cos x)^2$$

$$y' = 8x(2x^3+5)^3$$

$$y' = 24x^2(2x^3+5)^3$$

$$y' = 4(2x^3+5)^3$$

$$y' = 6x^2(2x^3+5)^4$$

$$y'=6tg^5x·\ \frac{1}{\cos^2x}$$

$$y' = 6tg^5 x$$

$$y'=\frac{1}{\cos^2x}$$

$$y'=\frac{5tg^4x·}{\sin^2x}$$

y' = cos(2x+3)

y' = 2·cos(2x+3)

y' = −2·sin(2x+3)

y' = 2·sin(2x+3)

$$y' = \frac{1}{x^2+5}$$

y' = 2x

$$y' = \frac{2x}{x^2 + 5}$$

$$y' = \frac{x^2+5}{2x}$$

y' = $$\frac{1}{(x+\sqrt{x^2+1)}}$$

$$y'=\frac{1}{\sqrt{x^2+1}}$$

$$y' = \frac{1}{x^2+1}$$

y' = $$\frac{\sqrt{x^2+1}}{1+x/\sqrt{x^2+1}}$$

$$y' = \frac{cos x}{\sqrt{4 \sin^2 x - 1}}$$

y' = $$\frac{1}{(\sqrt[]{2\sin x+1}+\sqrt[]{2\sin x-1)}}$$

y' = $$\frac{1}{2\sin x+1}$$

y' = $$\frac{\cos x}{\sqrt[]{2\sin x−1}+\sqrt[]{2\sin x+1}}$$

y' = $$2\sqrt{x^2+k}$$

y' = $$\frac{x^2}{\sqrt[]{x^2+k}}$$ + $$\frac{k}{2(x+\sqrt[]{x^2+k}}$$

$$y' = \sqrt{x^2 + k}$$

y' = $$2x\sqrt{x^2+k}$$

y' = $$0$$

$$y' = \frac{4x}{1 + x^4}$$

y' = $$\frac{1}{1-\frac{2x^2}{\left((1+x^4\right)^2}}$$

$$y' = \frac{4x(1 - x^4)}{1 + x^4}$$