

Lens Power and Hypermetropia Concepts
Interactive Video
•
Physics, Chemistry, Biology
•
9th - 12th Grade
•
Practice Problem
•
Hard
Emma Peterson
FREE Resource
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7 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary function of the app introduced in the video?
To provide video solutions for various subjects
To play educational games
To offer online tutoring sessions
To sell educational books
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the near point for a hypermetropic person as mentioned in the video?
3 centimeters
50 centimeters
25 centimeters
15 centimeters
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the context of hypermetropia, what does the term 'near point' refer to?
The closest distance at which the eye can see clearly
The distance at which the eye can see with maximum strain
The farthest distance at which the eye can see clearly
The distance at which the eye can see without any strain
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula used to calculate the focal length of the lens?
f = 1/(1/u - 1/v)
1/f = 1/v + 1/u
1/f = 1/u - 1/v
f = 1/(1/v - 1/u)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the power of the lens required for a hypermetropic person if the focal length is 50 cm?
0.5 diopters
1 diopter
2 diopters
3 diopters
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the power of a lens calculated in diopters?
10 divided by the focal length in centimeters
10 multiplied by the focal length in centimeters
100 divided by the focal length in centimeters
100 multiplied by the focal length in centimeters
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final power of the lens calculated in the video?
2 diopters
1 diopter
4 diopters
3 diopters
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