Understanding Discontinuity in Functions

Understanding Discontinuity in Functions

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to identify discontinuities in the function f(x) = ln(cotangent^2(x)) over the interval from 0 to 2π. It begins by outlining the conditions for continuity, emphasizing that cotangent squared x must be greater than zero and cotangent x must be defined. The tutorial then details the conditions for discontinuity, noting that discontinuities occur where cotangent x equals zero or is undefined. The video analyzes the graph of the cotangent function to identify specific x values where discontinuities occur, including x = 0, π/2, π, and 3π/2. The tutorial concludes by verifying these discontinuities using the graph.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function f(x) given in the problem?

f(x) = ln(sin^2(x))

f(x) = ln(cotangent^2(x))

f(x) = ln(tan^2(x))

f(x) = ln(cos^2(x))

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the domain of the natural log function?

x < 0

x ≤ 0

x = 0

x > 0

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For continuity, what must be true about cotangent squared x?

It must be greater than zero

It must be equal to zero

It must be less than zero

It must be undefined

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When does cotangent x cause discontinuity?

When cotangent x is zero or undefined

When cotangent x is equal to one

When cotangent x is positive

When cotangent x is negative

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where does cotangent x have vertical asymptotes?

At x = 0, π, 2π

At x = 3π/4

At x = π/4

At x = π/2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At which x values is cotangent x equal to zero in the interval [0, 2π)?

x = 0, π

x = π, 2π

x = π/2, 3π/2

x = π/4, 3π/4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is NOT a point of discontinuity for f(x) in the interval [0, 2π)?

x = π

x = 2π

x = π/2

x = 0

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