Understanding Differential Equations and Initial Value Problems

Understanding Differential Equations and Initial Value Problems

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.C.8B

Standards-aligned

Created by

Aiden Montgomery

FREE Resource

Standards-aligned

CCSS.8.EE.C.8B
The video tutorial explains how to solve an initial value problem for a differential equation. It begins by introducing the problem and the concept of derivatives. The tutorial then demonstrates solving the differential equation by integrating, leading to the general solution. Using the initial condition, the particular solution is determined. Finally, the solution is graphed and verified against the direction field to ensure accuracy.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial value problem discussed in the video?

dydx = 2x - 3, Y(1) = 6

dydx = -2x - 3, Y(1) = 6

dydx = -2x + 3, Y(1) = 6

dydx = 2x + 3, Y(1) = 6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the differential equation dydx = -2x + 3?

Divide by x

Integrate the function

Multiply by a constant

Differentiate the function

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution for the differential equation dydx = -2x + 3?

y(x) = -x^2 + 3x + C

y(x) = x^2 - 3x + C

y(x) = x^2 + 3x + C

y(x) = -x^2 - 3x + C

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do we find the particular solution for the initial value problem?

By differentiating the general solution

By using the initial condition Y(1) = 6

By setting x = 0

By integrating the general solution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the constant C in the particular solution?

C = 5

C = 4

C = 3

C = 2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the particular solution for the initial value problem?

y(x) = x^2 + 3x + 5

y(x) = x^2 + 3x + 4

y(x) = x^2 + 3x + 2

y(x) = x^2 + 3x + 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of graphing the direction field?

To determine the constant

To verify the solution

To find the derivative

To solve the equation

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